Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 18 of 59.
Yahya Haider said:
1 decade ago
60 km = 60 x 1000 m = 60000 m.
1 hour = 60 x 60 = 3600 seconds.
So, Length/Distance = Speed x Time.
= 60000 m/3600 s x 9 s.
= 149.999.
= nearly 150m.
Therefore option D is correct answer.
1 hour = 60 x 60 = 3600 seconds.
So, Length/Distance = Speed x Time.
= 60000 m/3600 s x 9 s.
= 149.999.
= nearly 150m.
Therefore option D is correct answer.
Farhat said:
1 decade ago
Speed = 60 km/hr.
Time = 9 sec.
Distance = ?
Then, 1 km = 1000 m.
1 hr = 3600 sec.
Because we are to find the distance in metre/sec.
60000*9/3600 = 15 m.
Time = 9 sec.
Distance = ?
Then, 1 km = 1000 m.
1 hr = 3600 sec.
Because we are to find the distance in metre/sec.
60000*9/3600 = 15 m.
Sushmitha said:
1 decade ago
Great explanations.
Ghule santosh said:
1 decade ago
Always train high speed that means m/s.
Swamy chukkala said:
10 years ago
Well,
In my view 36 sec ---- 600 mt.
So, 9 sec ----150 mt.
In my view 36 sec ---- 600 mt.
So, 9 sec ----150 mt.
Jdajose said:
10 years ago
Why don't we just convert 9 sec into hour? It would be easier to do the v = d/t formula.
9 s (1 min/60 s) (1 hr/60 min) = 0.0025 hr.
Then substitute: 60 km/hr = d/0.0025 hr.
D = 0.15 km/hr (1000 m).
Distance = 150 meters.
9 s (1 min/60 s) (1 hr/60 min) = 0.0025 hr.
Then substitute: 60 km/hr = d/0.0025 hr.
D = 0.15 km/hr (1000 m).
Distance = 150 meters.
Meenakshi said:
10 years ago
Thanks for all of you for the kind explanation it's very easy to understand.
ANNAMALAI said:
10 years ago
1 km = 1000 m.
60 km = 60000 m.
1 hr = 3600 sec.
= (60000/3600)*9 = 150m.
60 km = 60000 m.
1 hr = 3600 sec.
= (60000/3600)*9 = 150m.
Sudheer said:
10 years ago
How it come 50/3 m/sec? Can you tel me please?
Umesh said:
10 years ago
I just want to check how this module? That's way I comment here.
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