Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
609 comments Page 18 of 61.
Sachin said:
1 decade ago
This math is simple. But your explanation makes the math more easy to learn specially for beginner like me. Thanks a lot.
Anomi said:
8 years ago
@Charmi.
20%+70%+10%(1800) =100%,
10% is 1800,
so 10x1800 = 18000.
12600(70%) + 3600(20%) + 1800 (10%) = 18000 (100%).
20%+70%+10%(1800) =100%,
10% is 1800,
so 10x1800 = 18000.
12600(70%) + 3600(20%) + 1800 (10%) = 18000 (100%).
Shashi kant gupta said:
9 years ago
1hr = 60min and 1km = 1000m.
Let 1min = 6km.
And 1min = 60sec.
1000/60 = 16.6.
16.6 * 9 = 150m.
This is the answer.
Let 1min = 6km.
And 1min = 60sec.
1000/60 = 16.6.
16.6 * 9 = 150m.
This is the answer.
Christo said:
3 years ago
The length of the train can be anything! why are we taking distance from the initial point to the pole?
Please explain.
Please explain.
(10)
Madhan said:
1 decade ago
They asked to find length of the train? but we gave an answer of distance traveled in 9sec, how these answers are same?
Akshaya said:
2 years ago
Speed = (60 x 5/18)m/sec=(50/3)m/sec.
Length of the train = (Speed x Time).
Length of the train = (50/3 x 9)m = 150 m.
Length of the train = (Speed x Time).
Length of the train = (50/3 x 9)m = 150 m.
(13)
Samyyyy said:
2 months ago
@All.
When we are converting km to meters, we have to take 5/18 as the options given in meters. So we have to do it.
When we are converting km to meters, we have to take 5/18 as the options given in meters. So we have to do it.
(7)
Priya said:
6 years ago
@Koushik Reddy.
We use 5/18 to convert from km/hr to m/s in order to find the solution in terms of metres/seconds.
We use 5/18 to convert from km/hr to m/s in order to find the solution in terms of metres/seconds.
Sai Nath said:
1 decade ago
Length of the train = L.
L = Speed (s)*Time (T).
L = S*T.
L = 60*5/18*9.
L = 60*5/2.
L = 300/2=>L = 150 m.
L = Speed (s)*Time (T).
L = S*T.
L = 60*5/18*9.
L = 60*5/2.
L = 300/2=>L = 150 m.
R SUBRAMANI said:
10 years ago
Easy to improve our knowledge.
1 hour = 3600 secs.
1 km = 1000 m.
3600/1000 = 36/10 = 5/18.
60*5/18*9 = 150 m.
1 hour = 3600 secs.
1 km = 1000 m.
3600/1000 = 36/10 = 5/18.
60*5/18*9 = 150 m.
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