Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
643 comments Page 19 of 65.
Christo said:
4 years ago
The length of the train can be anything! why are we taking distance from the initial point to the pole?
Please explain.
Please explain.
(10)
Madhan said:
1 decade ago
They asked to find length of the train? but we gave an answer of distance traveled in 9sec, how these answers are same?
Akshaya said:
3 years ago
Speed = (60 x 5/18)m/sec=(50/3)m/sec.
Length of the train = (Speed x Time).
Length of the train = (50/3 x 9)m = 150 m.
Length of the train = (Speed x Time).
Length of the train = (50/3 x 9)m = 150 m.
(13)
Samyyyy said:
11 months ago
@All.
When we are converting km to meters, we have to take 5/18 as the options given in meters. So we have to do it.
When we are converting km to meters, we have to take 5/18 as the options given in meters. So we have to do it.
(7)
Priya said:
7 years ago
@Koushik Reddy.
We use 5/18 to convert from km/hr to m/s in order to find the solution in terms of metres/seconds.
We use 5/18 to convert from km/hr to m/s in order to find the solution in terms of metres/seconds.
Vanitha peddireddy said:
7 months ago
1km = 1000m
1h = 3600sec
Length = speed/time.
S = 1000/3600 = 5/18.
6 * 5/18 = 16.66667.
16.66667m/sec * 9 = 150m.
1h = 3600sec
Length = speed/time.
S = 1000/3600 = 5/18.
6 * 5/18 = 16.66667.
16.66667m/sec * 9 = 150m.
(14)
Sai Nath said:
1 decade ago
Length of the train = L.
L = Speed (s)*Time (T).
L = S*T.
L = 60*5/18*9.
L = 60*5/2.
L = 300/2=>L = 150 m.
L = Speed (s)*Time (T).
L = S*T.
L = 60*5/18*9.
L = 60*5/2.
L = 300/2=>L = 150 m.
R SUBRAMANI said:
1 decade ago
Easy to improve our knowledge.
1 hour = 3600 secs.
1 km = 1000 m.
3600/1000 = 36/10 = 5/18.
60*5/18*9 = 150 m.
1 hour = 3600 secs.
1 km = 1000 m.
3600/1000 = 36/10 = 5/18.
60*5/18*9 = 150 m.
Adeleye Jeremiah said:
2 years ago
Here it is asked for the length of the train and not the distance covered by the train. So anyone explain me this?
(4)
Madrid said:
3 years ago
60km/hr X (9s x 1min/60s x 1hr/60min) = 60km/hr * 2.5x10^-3hr.
km/hr * hr = km.
So, the answer is 0.15km or 150m.
km/hr * hr = km.
So, the answer is 0.15km or 150m.
(17)
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m/sec
Length of the train =