Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
598 comments Page 15 of 60.
Rubiya said:
1 decade ago
@Gowtham.
If train length is more then it takes more time to cross the pole. If it is small train then it takes less time to cross the pole.
If train length is more then it takes more time to cross the pole. If it is small train then it takes less time to cross the pole.
Surya said:
10 years ago
The word "thank you" is not for your explanation @Sunder. But I got one doubt evar bike also maintain same speed and then length of bike is?
Gurram bhargavi said:
2 years ago
Length of train = speed * time.
= 9 * 60 * 5/18(converting km/hr into m/sec).
= 150 meters.
= 9 * 60 * 5/18(converting km/hr into m/sec).
= 150 meters.
(32)
Vijay dabasiya said:
1 decade ago
Easy method.
1km=1000 m.
1 hr=3600 sec.
Formula length of = velocity*time.
= 60*1000/3600 *9.
= 150 m.
1km=1000 m.
1 hr=3600 sec.
Formula length of = velocity*time.
= 60*1000/3600 *9.
= 150 m.
Srinivas said:
9 years ago
Yeah@ obviously. Mr. Sundar your answer was right but I think your solution is complicated. I need as simple as possible. Will you provide?
SAI MOHAN REDDY said:
1 decade ago
In the above question we can change minutes for seconds.
60*5/18 = (50/3) m/sec.
Length of the train is = (Speed*Time) = 50/3*9 = 150 m.
60*5/18 = (50/3) m/sec.
Length of the train is = (Speed*Time) = 50/3*9 = 150 m.
Nrsp said:
11 months ago
Convert km/h to m/s.
1km = 1000m.
1hour = 3600sec.
Speed = 60km/h.
= 60 × 1000/3600,
= 60 × (5/18),
= 50/3.
1km = 1000m.
1hour = 3600sec.
Speed = 60km/h.
= 60 × 1000/3600,
= 60 × (5/18),
= 50/3.
(16)
SREENIVASULU said:
1 year ago
Given, S = 60 km/hr,
Time(T) = 9 sec and L(T)=?
Speed(S) = (60 * 5/18) = (50/3 m/sec).
L(T) = S * T.
L(T) = (50/3*9)m.
= 150m.
Time(T) = 9 sec and L(T)=?
Speed(S) = (60 * 5/18) = (50/3 m/sec).
L(T) = S * T.
L(T) = (50/3*9)m.
= 150m.
(10)
Kalden said:
1 decade ago
Guys nice explanation but I have confusion that km/hour and meter/sec. Then what about minute? Actually we should take meter/minute.
Sam said:
10 years ago
1000/60 = 16.666.
= 16.666x9 = 150.
One more 1000/10 = 100.
= 60/10 = 6.
= 100 mtr/6 sec.
= 50 mtr/3 sec.
So 150 mtr in 9 sec.
= 16.666x9 = 150.
One more 1000/10 = 100.
= 60/10 = 6.
= 100 mtr/6 sec.
= 50 mtr/3 sec.
So 150 mtr in 9 sec.
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Length of the train =