Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 14 of 59.
Asif Bilakhiya said:
7 years ago
Train Speed=60km/hr.
Take 9 seconds to cross the pole.
60km =60000 metres,
1hr=3600 seconds,
Ans=150 metres,
Explanation:
=(9x60000)/(3600),
=150 metres.
Take 9 seconds to cross the pole.
60km =60000 metres,
1hr=3600 seconds,
Ans=150 metres,
Explanation:
=(9x60000)/(3600),
=150 metres.
Hemanth Sairam said:
2 years ago
(60kms / 3600 secs) x 9 secs = 0.15kms
0.15kms in mtrs = 150 mtrs
If the train taken 3600 seconds to travel 60kms,
Then how much for 9 secs?
That’s it.
0.15kms in mtrs = 150 mtrs
If the train taken 3600 seconds to travel 60kms,
Then how much for 9 secs?
That’s it.
(48)
Arun said:
1 decade ago
To remember the formula velocity = d/t (M/s).
d is distance measured in metre(m).
T is the time taken in seconds(s).
So the unit of velocity is (m/s).
d is distance measured in metre(m).
T is the time taken in seconds(s).
So the unit of velocity is (m/s).
Akhil Joseph K J said:
6 months ago
Calculation: 60× (5 / 18)
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
(9)
Sagar said:
9 years ago
1 Hour = 60 Min.
1 Min = 60 Sec.
(Min * Sec = 60 * 60 = 3600).
3600 Sec= 60KM.
9 Sec = ?
60 * 9/3600= 0.15.
So, As per the Option Length is 150 MTR.
1 Min = 60 Sec.
(Min * Sec = 60 * 60 = 3600).
3600 Sec= 60KM.
9 Sec = ?
60 * 9/3600= 0.15.
So, As per the Option Length is 150 MTR.
Suresh said:
9 years ago
10/36 m/s
= 5/18 m/s.
Therefore 1 km/hr = 5/18 m/sec.
Similarly 60 km/hr = 60 x 5/18 m/sec.
I'm not understanding this section, please explain.
= 5/18 m/s.
Therefore 1 km/hr = 5/18 m/sec.
Similarly 60 km/hr = 60 x 5/18 m/sec.
I'm not understanding this section, please explain.
Kalimuthu said:
1 decade ago
1000m=1km so 60000m goes in 1hour.
1 hour=3600 sec so 60000/3600 =16.666 so train cross in 1 second is 16.666m...so 9 seconds 16.6666*9=150meter .
1 hour=3600 sec so 60000/3600 =16.666 so train cross in 1 second is 16.666m...so 9 seconds 16.6666*9=150meter .
(7)
Kopila said:
2 months ago
@All.
The answer here calculated is the distance of the train travelled in 9 seconds right, then how can you claim it as the length if the train?
The answer here calculated is the distance of the train travelled in 9 seconds right, then how can you claim it as the length if the train?
(6)
Sara said:
1 decade ago
Distance = Time *speed
1km =1000Meteres
1hr =3600 seconds
Distance = 60*9/3600 =9/60 km
Distane in Metres =(9/60)*1000 =150M
simple and fast way
1km =1000Meteres
1hr =3600 seconds
Distance = 60*9/3600 =9/60 km
Distane in Metres =(9/60)*1000 =150M
simple and fast way
Rubiya said:
1 decade ago
@Gowtham.
If train length is more then it takes more time to cross the pole. If it is small train then it takes less time to cross the pole.
If train length is more then it takes more time to cross the pole. If it is small train then it takes less time to cross the pole.
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