Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
598 comments Page 14 of 60.
Priyanka padhi said:
1 decade ago
Thanks @Sundar. That's was a very nice explanation. For those who are not strong in this section, this is the best way to make them easily understandable.
Asif Bilakhiya said:
8 years ago
Train Speed=60km/hr.
Take 9 seconds to cross the pole.
60km =60000 metres,
1hr=3600 seconds,
Ans=150 metres,
Explanation:
=(9x60000)/(3600),
=150 metres.
Take 9 seconds to cross the pole.
60km =60000 metres,
1hr=3600 seconds,
Ans=150 metres,
Explanation:
=(9x60000)/(3600),
=150 metres.
Hemanth Sairam said:
2 years ago
(60kms / 3600 secs) x 9 secs = 0.15kms
0.15kms in mtrs = 150 mtrs
If the train taken 3600 seconds to travel 60kms,
Then how much for 9 secs?
That’s it.
0.15kms in mtrs = 150 mtrs
If the train taken 3600 seconds to travel 60kms,
Then how much for 9 secs?
That’s it.
(48)
Arun said:
1 decade ago
To remember the formula velocity = d/t (M/s).
d is distance measured in metre(m).
T is the time taken in seconds(s).
So the unit of velocity is (m/s).
d is distance measured in metre(m).
T is the time taken in seconds(s).
So the unit of velocity is (m/s).
Akhil Joseph K J said:
9 months ago
Calculation: 60× (5 / 18)
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
(9)
Sagar said:
9 years ago
1 Hour = 60 Min.
1 Min = 60 Sec.
(Min * Sec = 60 * 60 = 3600).
3600 Sec= 60KM.
9 Sec = ?
60 * 9/3600= 0.15.
So, As per the Option Length is 150 MTR.
1 Min = 60 Sec.
(Min * Sec = 60 * 60 = 3600).
3600 Sec= 60KM.
9 Sec = ?
60 * 9/3600= 0.15.
So, As per the Option Length is 150 MTR.
Suresh said:
9 years ago
10/36 m/s
= 5/18 m/s.
Therefore 1 km/hr = 5/18 m/sec.
Similarly 60 km/hr = 60 x 5/18 m/sec.
I'm not understanding this section, please explain.
= 5/18 m/s.
Therefore 1 km/hr = 5/18 m/sec.
Similarly 60 km/hr = 60 x 5/18 m/sec.
I'm not understanding this section, please explain.
Kalimuthu said:
1 decade ago
1000m=1km so 60000m goes in 1hour.
1 hour=3600 sec so 60000/3600 =16.666 so train cross in 1 second is 16.666m...so 9 seconds 16.6666*9=150meter .
1 hour=3600 sec so 60000/3600 =16.666 so train cross in 1 second is 16.666m...so 9 seconds 16.6666*9=150meter .
(7)
Kopila said:
5 months ago
@All.
The answer here calculated is the distance of the train travelled in 9 seconds right, then how can you claim it as the length if the train?
The answer here calculated is the distance of the train travelled in 9 seconds right, then how can you claim it as the length if the train?
(7)
Sara said:
1 decade ago
Distance = Time *speed
1km =1000Meteres
1hr =3600 seconds
Distance = 60*9/3600 =9/60 km
Distane in Metres =(9/60)*1000 =150M
simple and fast way
1km =1000Meteres
1hr =3600 seconds
Distance = 60*9/3600 =9/60 km
Distane in Metres =(9/60)*1000 =150M
simple and fast way
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