Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
626 comments Page 13 of 63.
Rashmi said:
5 years ago
60km = 1hr
60km = 60min
so 1km = 1min.
1km = 1000metres, 1min=60sec
then 1000 = 60 sec
cancelation,
For 100=6,
50=3,
150=9,
Here 9 sec 150 metres.
60km = 60min
so 1km = 1min.
1km = 1000metres, 1min=60sec
then 1000 = 60 sec
cancelation,
For 100=6,
50=3,
150=9,
Here 9 sec 150 metres.
Santoshi Nayak said:
3 years ago
To find the length we can use the formula is length = speed * time.
Speed = 60km/hr
Pole = 9second
The length of the train would be 60*9/3600 = 0.15km or 150 meters.
Speed = 60km/hr
Pole = 9second
The length of the train would be 60*9/3600 = 0.15km or 150 meters.
(17)
Siddhesh Anavkar said:
8 years ago
Formula.
1. Distance = speed * time
2. km/hr --> m/sec conversion
For ex. convert 90 km/hr to m/sec
Solution:-
90 km/1 hr = 90,000 m/3600 sec
= 25 m/sec.
1. Distance = speed * time
2. km/hr --> m/sec conversion
For ex. convert 90 km/hr to m/sec
Solution:-
90 km/1 hr = 90,000 m/3600 sec
= 25 m/sec.
Subhasri said:
1 decade ago
Another easy method for solving it.
In 3600 sec the train go 60 km.
In 1 sec the train will go 1/60km.
Then in 9 sec it will go (1/60) *9 = .15km = 150 meter.
In 3600 sec the train go 60 km.
In 1 sec the train will go 1/60km.
Then in 9 sec it will go (1/60) *9 = .15km = 150 meter.
Sandeep said:
1 decade ago
Firsst 60 km/sec need to be converted in to meter /second.
It could be by multiply by 60*5/18 and then it multiply by 9 secound and hence anse we get 150 meter.
It could be by multiply by 60*5/18 and then it multiply by 9 secound and hence anse we get 150 meter.
Vikas said:
9 years ago
If you divide 1000/3600 = 0.27.
But it is showing 10/36 after that 5/18.
I am not understanding how it came 10/36 then 5/18?
Please help me by explaining it.
But it is showing 10/36 after that 5/18.
I am not understanding how it came 10/36 then 5/18?
Please help me by explaining it.
Bahauddin said:
7 years ago
Some thing is missing in the question and solution because if train crosses the pole means train will has to cross the extra length as much the length of train.
Jayanthi said:
1 decade ago
Lets take mnthy salry to be x;
then ,
x-15x/100+55x/100=12750;
x-14x/20=12750;
6x/20=12750;
x=(12750)20/6
x=42,5000;
monthly salry is Rs.42,500
then ,
x-15x/100+55x/100=12750;
x-14x/20=12750;
6x/20=12750;
x=(12750)20/6
x=42,5000;
monthly salry is Rs.42,500
Farhat said:
1 decade ago
Speed = 60 km/hr.
Time = 9 sec.
Distance = ?
Then, 1 km = 1000 m.
1 hr = 3600 sec.
Because we are to find the distance in metre/sec.
60000*9/3600 = 15 m.
Time = 9 sec.
Distance = ?
Then, 1 km = 1000 m.
1 hr = 3600 sec.
Because we are to find the distance in metre/sec.
60000*9/3600 = 15 m.
Vivek said:
8 years ago
We calculated the train length with reference to the pole. But what about the length of the pole. Doesn't it come to picture here?
Please, anyone, clarify it.
Please, anyone, clarify it.
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