Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
592 comments Page 15 of 60.
SRUJANKUMAR said:
3 years ago
The speed of train in 1sec =(60*5)/18=16.66666666666667 m/sec,
As we know that an object or a thing can be crossed with the length of a train
we took 9sec then
The length of train = 16.66666666666667 * 9 = 150 m.
As we know that an object or a thing can be crossed with the length of a train
we took 9sec then
The length of train = 16.66666666666667 * 9 = 150 m.
(14)
Shyam Prasanth said:
3 years ago
= 60×5/18.
= 300/18 (50×6=300 ,3×6=18).
= 50/3,
= 50/3×9,
= 50×3,
= 150.
= 300/18 (50×6=300 ,3×6=18).
= 50/3,
= 50/3×9,
= 50×3,
= 150.
(12)
Nagarur Yeswanth said:
3 years ago
60 *5/18 = 50/3.
450m/3 = 150m.
450m/3 = 150m.
(6)
Samridhi said:
3 years ago
Speed = 60 km/hr= 60* (5/18) m/s = 16.67 m/s.
Time= 9 sec.
Distance = speed* time.
Distance = 16.67 * 9 =150m.
Time= 9 sec.
Distance = speed* time.
Distance = 16.67 * 9 =150m.
(8)
Murali said:
3 years ago
Length = time/speed.
= 9sec/60kmhr.
= 0.15km = 150meter.
= 9sec/60kmhr.
= 0.15km = 150meter.
(49)
K Nithish said:
3 years ago
How come 5/18? Please explain me.
(67)
Nilesh avhad said:
3 years ago
600 % 36 = 16.67.
16.67 * 9 = 150.
16.67 * 9 = 150.
(13)
NARINDER KUMAR said:
3 years ago
9 = D*18/60 * 5 (USE S=D/T) AND (COVERT KM/HOUR IN TO M/SEC ) * 5/18.
So,
1 = D*2/300,
D = 300/2,
D = 150.
So,
1 = D*2/300,
D = 300/2,
D = 150.
(5)
Pavitra said:
3 years ago
1m = 1/1000km and
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
(30)
BikramTisso said:
3 years ago
Thanks for the explanation @Kenshika venistran.
(7)
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