Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
592 comments Page 14 of 60.
Rajesh N Madavi said:
2 years ago
Time = Length of the train/Speed of the train.
Time is in seconds, do speed should be in metres/Seconds.
60 km/hr = 60 × 5/18 m/s = 50/3 m/s.
9 seconds = length/50/3.
9 × 50/3 = length.
length = 3 × 50 = 150 metre.
Time is in seconds, do speed should be in metres/Seconds.
60 km/hr = 60 × 5/18 m/s = 50/3 m/s.
9 seconds = length/50/3.
9 × 50/3 = length.
length = 3 × 50 = 150 metre.
(13)
Narayan Karki said:
2 years ago
Where,
Speed = Distance(s)/Time(t).
To convert speed into m/s from km/hr.
Then, use the formula = Speed x Time = 100/6 * 9 = 150m.
Speed = Distance(s)/Time(t).
To convert speed into m/s from km/hr.
Then, use the formula = Speed x Time = 100/6 * 9 = 150m.
(20)
Wick said:
2 years ago
@All.
Here, 5/18 is used to convert Km/hr to m/s.
Here, 5/18 is used to convert Km/hr to m/s.
(30)
Threennath said:
2 years ago
How we get 5/18? please explain to me.
(49)
Manikandan said:
2 years ago
Data:
T=9,
S=?,
L=?
Time = length/seconds.
S = 60*5/18.
S = 16.6666,
T = L/S.
9 = L/16.6666,
L = 9×16.6666,
L = 149.9,
L = 150.
T=9,
S=?,
L=?
Time = length/seconds.
S = 60*5/18.
S = 16.6666,
T = L/S.
9 = L/16.6666,
L = 9×16.6666,
L = 149.9,
L = 150.
(22)
Faheem said:
2 years ago
How did the 5/18 came? Can anyone explain it?
(38)
Sumanth kumar said:
2 years ago
First convert the unit km/hr into m/s, because the length of the train is given in meters.
->so ,1km=1000m and 1 hr=1*60*60=3600 secs.
Now ,as we all know, the formula for speed in terms of distance is
speed =distance /time.
=>(60*1000/3600) m/s = distance/9 secs.
=>60*5/18 = length of train/9(time taken to cross the pole by train)
=>9*60*5/18 = length of the train.
=>length of the train =150 m.
->so ,1km=1000m and 1 hr=1*60*60=3600 secs.
Now ,as we all know, the formula for speed in terms of distance is
speed =distance /time.
=>(60*1000/3600) m/s = distance/9 secs.
=>60*5/18 = length of train/9(time taken to cross the pole by train)
=>9*60*5/18 = length of the train.
=>length of the train =150 m.
(71)
Sandip Thaware said:
2 years ago
Here we can use the formula;
The time taken by train to cross an object (i.e. man, pole, tree etc.)
T = L/S.
where T= time taken by train to cross an object.
L= Length of the train.
S= Speed of Train.
we have, S = 60 km/hr.
S = 60 * 5/18 ('*' symbol used for multiplication)
S = 16.66666 meter/second
T = 9 seconds.
Now, 9 = L/16.66666.
L = 9 * 16.
L = 149.99994~ 150 meter .
Answer = 150 meters.
The time taken by train to cross an object (i.e. man, pole, tree etc.)
T = L/S.
where T= time taken by train to cross an object.
L= Length of the train.
S= Speed of Train.
we have, S = 60 km/hr.
S = 60 * 5/18 ('*' symbol used for multiplication)
S = 16.66666 meter/second
T = 9 seconds.
Now, 9 = L/16.66666.
L = 9 * 16.
L = 149.99994~ 150 meter .
Answer = 150 meters.
(9)
Pavan sai Rama said:
2 years ago
(MLT) Medical Lab Technician.
(5)
Arun s said:
2 years ago
1 km = 1000 m,
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
(94)
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