Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 6 of 8.
Prashants.s.wagge said:
1 decade ago
Just solve in simp way.
1st 3 odd int are 1, 3, 5.
Add those 1+3+5 = 9.
Now take 3 odd num after 9 i.e. = 15.
1st 3 odd int are 1, 3, 5.
Add those 1+3+5 = 9.
Now take 3 odd num after 9 i.e. = 15.
Nani said:
1 decade ago
If we take three consecutive numbers are x, x+2, x+4....
If we substitute x as 1 (because 1 is the 1st odd num).
We get odd numbers.....1, 3, 5..
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4).
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
If we substitute x as 1 (because 1 is the 1st odd num).
We get odd numbers.....1, 3, 5..
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4).
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
Kamal said:
1 decade ago
How can we take x, x+2, x+4 as odd positive integers. Kindly clear my doubt?
Nusohel said:
1 decade ago
Three conservatives odd integers are X, X+2, X+4
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4)
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4)
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
Santhosh said:
1 decade ago
Three consecutive odd integers are x+1, x+3, x+5
So,
3(x+1) = 3+2(x+5).
3x+3 = 3 + 2x + 10.
x = 10. So the third number is x+5.
10+5 = 15.
Answer 15.
So,
3(x+1) = 3+2(x+5).
3x+3 = 3 + 2x + 10.
x = 10. So the third number is x+5.
10+5 = 15.
Answer 15.
Rashmi said:
1 decade ago
Hi,
Consecutive nos are x, x+2, x+4. If we add 1 to these nos we get odd consecutive nos.
So read the question neatly.
3 times the first of three consecutive nos it means first consecutive no is x. 3 times means 3x.
So answer is 15.
Consecutive nos are x, x+2, x+4. If we add 1 to these nos we get odd consecutive nos.
So read the question neatly.
3 times the first of three consecutive nos it means first consecutive no is x. 3 times means 3x.
So answer is 15.
Sukruthi said:
1 decade ago
As they hav given 3 consecutive odd integers then that 3 can be assumed as 2x+1,2x+3,2x+5 ...
because x,x+2,x+4 wont give us odd values if v substitute any positive integers. then the values which i have assumed can satisfy all consecutive odd integers so now
1st of 3 consecutive integers is 2x+1
so now 3*(2x+1)=3+(2*(2x+5)
=> 6x+3=4x+13
=> x=5
now 3rd integer is
2x+5
=> 2(5)+5=15.
because x,x+2,x+4 wont give us odd values if v substitute any positive integers. then the values which i have assumed can satisfy all consecutive odd integers so now
1st of 3 consecutive integers is 2x+1
so now 3*(2x+1)=3+(2*(2x+5)
=> 6x+3=4x+13
=> x=5
now 3rd integer is
2x+5
=> 2(5)+5=15.
Keerthi said:
1 decade ago
How we take x, x+2, x+4 are odd integers if we take x=2 then it become even can any one clear this doubt ?
Satish said:
1 decade ago
Hi all,
1> See it is said that first of 3 consecutive odd no is 3.
2> It is said 3 times the first no means i.e. 3*3 = 9.
3> It is also said that 3rd no is 3 more or twice the first i.e. 6.
4> That's how we get the answer 9+6=15.
1> See it is said that first of 3 consecutive odd no is 3.
2> It is said 3 times the first no means i.e. 3*3 = 9.
3> It is also said that 3rd no is 3 more or twice the first i.e. 6.
4> That's how we get the answer 9+6=15.
Prerak said:
1 decade ago
Hey can anyone explain this problem? I don't understand these "odd integers is 3 more than twice the third".
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