# Aptitude - Problems on Numbers - Discussion

Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)

2.

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

Answer: Option

Explanation:

Let the three integers be *x*, *x* + 2 and *x* + 4.

Then, 3*x* = 2(*x* + 4) + 3 *x* = 11.

Third integer = *x* + 4 = 15.

Video Explanation: https://youtu.be/_77C9YE321Y

Discussion:

75 comments Page 8 of 8.
Nishanthi said:
1 decade ago

Here 3 more than that of the value of x so we use.

3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.

3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.

Bharghavi said:
1 decade ago

The answer would be 9.

Explanation:

Suppose 3 nos. are x,x+2,x+4

The equations would be

3x+3=2(x+4),therefore x=5

So, the third no. is x+4=5+4=9.

Explanation:

Suppose 3 nos. are x,x+2,x+4

The equations would be

3x+3=2(x+4),therefore x=5

So, the third no. is x+4=5+4=9.

Sandeep pote said:
1 decade ago

Third integer would be 9.

Explanation:

Suppose 3 numbers are . . x, x+2, x+4.

3x = 2(x + 4) - 3

3x = 2x + 8 -3

x = 5

Then third number is 5 + 4 = 9.

Explanation:

Suppose 3 numbers are . . x, x+2, x+4.

3x = 2(x + 4) - 3

3x = 2x + 8 -3

x = 5

Then third number is 5 + 4 = 9.

Nilesh said:
1 decade ago

0 is considerd as even number.

Saji said:
1 decade ago

Hai can any one clear my doubt. They have mentioned it as three consecutive odd integers. If 0 is substituted in the place of x it becomes three even integers.

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