Aptitude - Problems on Numbers - Discussion

Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
9
11
13
15
Answer: Option
Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3      x = 11.

Third integer = x + 4 = 15.

Video Explanation: https://youtu.be/_77C9YE321Y

Discussion:
74 comments Page 8 of 8.

Bharghavi said:   1 decade ago
The answer would be 9.

Explanation:
Suppose 3 nos. are x,x+2,x+4
The equations would be

3x+3=2(x+4),therefore x=5

So, the third no. is x+4=5+4=9.

Sandeep pote said:   1 decade ago
Third integer would be 9.

Explanation:

Suppose 3 numbers are . . x, x+2, x+4.

3x = 2(x + 4) - 3

3x = 2x + 8 -3

x = 5

Then third number is 5 + 4 = 9.

Nilesh said:   1 decade ago
0 is considerd as even number.

Saji said:   1 decade ago
Hai can any one clear my doubt. They have mentioned it as three consecutive odd integers. If 0 is substituted in the place of x it becomes three even integers.


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