Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 8 of 8.
Nishanthi said:
1 decade ago
Here 3 more than that of the value of x so we use.
3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.
3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.
Bharghavi said:
1 decade ago
The answer would be 9.
Explanation:
Suppose 3 nos. are x,x+2,x+4
The equations would be
3x+3=2(x+4),therefore x=5
So, the third no. is x+4=5+4=9.
Explanation:
Suppose 3 nos. are x,x+2,x+4
The equations would be
3x+3=2(x+4),therefore x=5
So, the third no. is x+4=5+4=9.
Sandeep pote said:
1 decade ago
Third integer would be 9.
Explanation:
Suppose 3 numbers are . . x, x+2, x+4.
3x = 2(x + 4) - 3
3x = 2x + 8 -3
x = 5
Then third number is 5 + 4 = 9.
Explanation:
Suppose 3 numbers are . . x, x+2, x+4.
3x = 2(x + 4) - 3
3x = 2x + 8 -3
x = 5
Then third number is 5 + 4 = 9.
Nilesh said:
1 decade ago
0 is considerd as even number.
Saji said:
1 decade ago
Hai can any one clear my doubt. They have mentioned it as three consecutive odd integers. If 0 is substituted in the place of x it becomes three even integers.
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