Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 3 of 8.
Rashmi said:
1 decade ago
Hi,
Consecutive nos are x, x+2, x+4. If we add 1 to these nos we get odd consecutive nos.
So read the question neatly.
3 times the first of three consecutive nos it means first consecutive no is x. 3 times means 3x.
So answer is 15.
Consecutive nos are x, x+2, x+4. If we add 1 to these nos we get odd consecutive nos.
So read the question neatly.
3 times the first of three consecutive nos it means first consecutive no is x. 3 times means 3x.
So answer is 15.
Ssgm said:
1 decade ago
An integer n any odd will be (2n+1).
After (2n+1) is (2n+3) then (2n+5).
From the Q:
3(2n+1) > 2(2n+5).
=> n > 3.5 => n start from 4 to infinity.
So the numbers (2(4)+1=9), 11, 13 and I say the answer is 13.
After (2n+1) is (2n+3) then (2n+5).
From the Q:
3(2n+1) > 2(2n+5).
=> n > 3.5 => n start from 4 to infinity.
So the numbers (2(4)+1=9), 11, 13 and I say the answer is 13.
Nusohel said:
1 decade ago
Three conservatives odd integers are X, X+2, X+4
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4)
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4)
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
Chandan kumar said:
7 years ago
Let first consecutive odd integer=x+1,
second consecutive odd integer= x+3,
Third consecutive odd integer=x+5,
3(x+1)=2(x+5)+3,
3x+3= 2x+10+3,
3x-2x=13-3,
x=10.
Third consecutive odd integer=x+5,
= 10+5,
= 15.
second consecutive odd integer= x+3,
Third consecutive odd integer=x+5,
3(x+1)=2(x+5)+3,
3x+3= 2x+10+3,
3x-2x=13-3,
x=10.
Third consecutive odd integer=x+5,
= 10+5,
= 15.
Mahin said:
6 years ago
The Consecutive odd integers are (2x+1, 2x+3, 2x+5). Sub any no.for 'x', you'll get an odd integer.
Now, try solving the question with these three, you'll get X = 5;
That means the 3rd integer, 2X + 5 = 15.
Now, try solving the question with these three, you'll get X = 5;
That means the 3rd integer, 2X + 5 = 15.
(3)
Vicky said:
9 years ago
Here is the perfect answer.
Let 3 numbers be x + 1, x + 3, x + 5.
3 (x + 1) = 3 + 2 (x + 5).
Simplify it then you will get x = 5,
Then substitute x in x + 5.
10 + 5 = 15.
Therefore, 15 is the answer.
Let 3 numbers be x + 1, x + 3, x + 5.
3 (x + 1) = 3 + 2 (x + 5).
Simplify it then you will get x = 5,
Then substitute x in x + 5.
10 + 5 = 15.
Therefore, 15 is the answer.
Learner said:
1 decade ago
I believe when integers have been mentioned in the question and not positive or negative so better to have them as
2x-1, x, 2x+1.... and then solve the problem.
So the third integer comes out to be 9.
2x-1, x, 2x+1.... and then solve the problem.
So the third integer comes out to be 9.
V.Ranjitha said:
1 decade ago
Hi friends,
I think Govind is correct. Because the x value may be odd number or even number.(2x+1,2x+3,2x+5)
If x=0,
We get 1, 3, 5.
If x=1(odd),
We get 3, 5, 7.
If x=2(even),
We get 5, 7, 9.
I think Govind is correct. Because the x value may be odd number or even number.(2x+1,2x+3,2x+5)
If x=0,
We get 1, 3, 5.
If x=1(odd),
We get 3, 5, 7.
If x=2(even),
We get 5, 7, 9.
Neeraj upadhyay said:
1 decade ago
Three consecutive integer are 2x+1, 2x+3, 2x+5.
Now according to question.
3(2x+1) = 2(2x+5)+3.
6x+3 = 4x+10+3.
2x = 10.
x = 5.
And now third number is 2x+5 = 2*5+5 = 15.
15 is a answer.
Now according to question.
3(2x+1) = 2(2x+5)+3.
6x+3 = 4x+10+3.
2x = 10.
x = 5.
And now third number is 2x+5 = 2*5+5 = 15.
15 is a answer.
HEMANTH REDDY G said:
1 decade ago
3 times of 1st consecutive means 3x.
Twice of 3rd consecutive 2(x+4).
3 more than twice of 3rd consecutive 2(x+4)+3, then.
3x = 2(x+4)+3.
3x-2x = 8+3.
x = 11.
3rd integer is x+4 = 11+4 = 15.
Twice of 3rd consecutive 2(x+4).
3 more than twice of 3rd consecutive 2(x+4)+3, then.
3x = 2(x+4)+3.
3x-2x = 8+3.
x = 11.
3rd integer is x+4 = 11+4 = 15.
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