Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 2 of 8.
Swetha said:
1 decade ago
In this problem, they had given three consecutive odd integers.
If we take that 3 odd integers as x , x+2 and x+4,
if we put x = 2 => the numbers will become 2 , 4, 6
these nos are even numbers..then how we assume X,X+2,X+4 as three consecutive odd integers?
Can anyone Clear my doubt??
If we take that 3 odd integers as x , x+2 and x+4,
if we put x = 2 => the numbers will become 2 , 4, 6
these nos are even numbers..then how we assume X,X+2,X+4 as three consecutive odd integers?
Can anyone Clear my doubt??
Geetha said:
1 decade ago
What they said in question in three consecutive odd numbers, first number 3 times and 2 times of 3 rd number different is 3.
So we can consider that number should be like this.
x, x+2, x+4.
3x-2 (x+4) = 3.
x-8 = 3.
x = 11.
They asked about the third number so it is x+4 = 11+4 = 15.
So we can consider that number should be like this.
x, x+2, x+4.
3x-2 (x+4) = 3.
x-8 = 3.
x = 11.
They asked about the third number so it is x+4 = 11+4 = 15.
A.M.M said:
8 years ago
Let the three consecutive old numbers be; x+3, x+5, x+7,
3 times the first odd num = 3(x+3).
2 times the third odd num = 2(x+7) +3(which is in the question
3(x+3)=2(x+7)+3,
=3x+9=2x+14+3,
3x-2x=14+3-9,
x = 8.
Now to know what the the third integer is (x+7),
So x =8+7,
=15.
3 times the first odd num = 3(x+3).
2 times the third odd num = 2(x+7) +3(which is in the question
3(x+3)=2(x+7)+3,
=3x+9=2x+14+3,
3x-2x=14+3-9,
x = 8.
Now to know what the the third integer is (x+7),
So x =8+7,
=15.
Gayathri Ganesan said:
10 years ago
I got idea about this solution. But if we assume the solution by question as,
3 times the x of three consecutive integers whether is my assumption also possible na.
3(x+X+2+x+4) = 3+2(x+4) // I consider it for first 3 con int respectively.
Anyone can explain my logic please.
3 times the x of three consecutive integers whether is my assumption also possible na.
3(x+X+2+x+4) = 3+2(x+4) // I consider it for first 3 con int respectively.
Anyone can explain my logic please.
Sanjay said:
10 years ago
Simple way to solve problem z that, 3 times the x of 3 consecutive integers.
So, he said about odd numbers, now we take 3 consecutive are x, x+2, x+4, then we know odd numbers are 1, 3, 5, 7, 9,... so, take first 3 odd numbers and place like this, x+x+2+x+4, 1+3+2+5+4 = 15.
So, he said about odd numbers, now we take 3 consecutive are x, x+2, x+4, then we know odd numbers are 1, 3, 5, 7, 9,... so, take first 3 odd numbers and place like this, x+x+2+x+4, 1+3+2+5+4 = 15.
Lavanya said:
5 years ago
Let three consecutive odd integers are: x, x+2,x+4.
Three times the first of three integers, so--> 3x; is 3 more than twice the third so--> 3+ 2(x+4).
Then, we get an equation like 3x=3+2(x+4).
=3+2x+8.
3x-2x=11
X=11.
So, the third integer is x+4=15.
Three times the first of three integers, so--> 3x; is 3 more than twice the third so--> 3+ 2(x+4).
Then, we get an equation like 3x=3+2(x+4).
=3+2x+8.
3x-2x=11
X=11.
So, the third integer is x+4=15.
(9)
Gayathri said:
1 decade ago
Three consecutive odd numbers x+1, x+3, x+5.
(x+1)+(x+3)+(x+5) = 3+2(x+5).
x = 4. So the third integer x+5 = 4+5 = 9.
I think the answer will be 9 because in this problem three consecutive odd numbers is asked then, how can we start with 0 is my doubt.
(x+1)+(x+3)+(x+5) = 3+2(x+5).
x = 4. So the third integer x+5 = 4+5 = 9.
I think the answer will be 9 because in this problem three consecutive odd numbers is asked then, how can we start with 0 is my doubt.
Megersa said:
8 years ago
Three consecutive integers are: x, x+2 &x+4 but if it says three times the first of three consecutive, it means that 3 (x+x+2+x+4) not 3x, so doing by this method the result becomes negative integer, so by itself, the question has its own problem.
Mahaprasad said:
9 years ago
Answer can be 11 also !
Suppose 7,9,11 are the hree consecutive odd numbers!
If the first number will be 7. Three times of 7 would be 21!
2 times of second number(9) would be 18.
21 is greater than 18 by 3 number.
So it justifies the equation.
Suppose 7,9,11 are the hree consecutive odd numbers!
If the first number will be 7. Three times of 7 would be 21!
2 times of second number(9) would be 18.
21 is greater than 18 by 3 number.
So it justifies the equation.
Satish said:
1 decade ago
Hi all,
1> See it is said that first of 3 consecutive odd no is 3.
2> It is said 3 times the first no means i.e. 3*3 = 9.
3> It is also said that 3rd no is 3 more or twice the first i.e. 6.
4> That's how we get the answer 9+6=15.
1> See it is said that first of 3 consecutive odd no is 3.
2> It is said 3 times the first no means i.e. 3*3 = 9.
3> It is also said that 3rd no is 3 more or twice the first i.e. 6.
4> That's how we get the answer 9+6=15.
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