Aptitude - Problems on Numbers - Discussion

Zero included in a set of whole numbers. So if we start putting 1, 3, 5 .....in x, we get the consecutive odd numbers only!!

Answer can be 11 also !
Suppose 7,9,11 are the hree consecutive odd numbers!

If the first number will be 7. Three times of 7 would be 21!
2 times of second number(9) would be 18.
21 is greater than 18 by 3 number.
So it justifies the equation.

Here is the perfect answer.

Let 3 numbers be x + 1, x + 3, x + 5.
3 (x + 1) = 3 + 2 (x + 5).

Simplify it then you will get x = 5,
Then substitute x in x + 5.
10 + 5 = 15.

Therefore, 15 is the answer.

Instead of that directly can't we take 1, 3, 5.

Let the three odd integers be x, x + 2 and x + 4.

(we know Integers I = 1, 2, 3, ....).

If x = 1 then,

The three integers are {sub x=1 in x, x + 2 and x + 4. } --> 1, 3, 5 => which are odd.

Three times the first of three consecutive odd integers (Which is 3x) is 3 more than (add +3) twice the third [2 (x + 4) ].

=> 3x = 2 (x + 4) + 3,

=> x = 11.

Since we got "x" value, we have to find the third integer value i.e. x + 4 value.

=> Third integer = x + 4 = 11+ 4 = 15.

Hope you get this.

Let the three odd integers be x, x + 2 and x + 4.

(Integer = 1, 2 , 3).

If x = 1 then the three integers are 1, 3, 5 => which are odd.

Three times the first of three consecutive odd integers (Which is 3x) is.

3 more than (+3) twice the third [2 (x + 4) ] => 3x = 2 (x + 4) + 3x = 11.

Since we got "x", we have to find the third integer value i.e. x + 4 value.

=> Third integer = x + 4 = 15.

Hope you get this.

Why we go through option answers.

Three times the first = 3 (first number).
Twice the third one = 2 (third number).
3 more than that = 3 + 2 (third number).

To find the third number;

So, we apply the option a (or) b (or) c (or) d.

The first option is 9 if the third integer is 9 then the three odd numbers are 5, 7, 9.

=>So 3 (5) is not equal to 3 + 2 (9).

Option b = 11.

So, the numbers are 7, 9, 11.

=>3 (7) is not equal to 3 + 2 (11).

So let's try option d = 15.

The three odd numbers 11, 13, 15.

=> 3 (11) is equal to 3 + 2 (15).

So, the answer is 15.

0 is an even number, about what basis the given question doesn't take o is let me assume if we take consecutive no i.e. X+0=0, so we took directly "X".

Answer: 13.

Because 11 + 13 = 24.

9*3 = 27.
27-24 = 3.

Simple way to solve problem z that, 3 times the x of 3 consecutive integers.

So, he said about odd numbers, now we take 3 consecutive are x, x+2, x+4, then we know odd numbers are 1, 3, 5, 7, 9,... so, take first 3 odd numbers and place like this, x+x+2+x+4, 1+3+2+5+4 = 15.