Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 25)
25.
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
Answer: Option
Explanation:
Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.
Discussion:
30 comments Page 3 of 3.
Unknown said:
9 years ago
Please tell me how to find the HCF of 15, 12, 20, 54.
Disha said:
1 decade ago
After calculating the lcm why 8 is added?
V!cky said:
10 years ago
Just add remainder with it 540+8 = 548.
Saritha said:
1 decade ago
wat is the lcm of 12,15,20 and 54?
Anon said:
10 years ago
Shouldn't the answer be 8 here?
Ayesha said:
1 decade ago
Yes why it is not like 540k+8?
Abdul said:
1 decade ago
Please explain the sum to me.
Jas said:
1 decade ago
How?
Anybody can explain ?
Anybody can explain ?
Shakti said:
1 decade ago
Yes why it is not 540k+8?
(1)
Saranya said:
1 decade ago
lcm=540
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