Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 25)
25.
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
504
536
544
548
Answer: Option
Explanation:

Required number = (L.C.M. of 12, 15, 20, 54) + 8

   = 540 + 8

   = 548.

Discussion:
30 comments Page 1 of 3.

Saritha said:   1 decade ago
wat is the lcm of 12,15,20 and 54?

Saranya said:   1 decade ago
lcm=540

Jas said:   1 decade ago
How?

Anybody can explain ?

Prannav said:   1 decade ago
Can anyone please show me the procedure to calculate the lcm as I think I am making some mistake.

Suresh said:   1 decade ago
First divide entire given series with 2 then you have the remainders 6, 15, 10, 27.

Now divide these series with 3 then you get reminders 2, 5, 10, 9.

Now divide before series with 5 then you will get series 2, 1, 2, 9.

Now divide before series with 2 then you will get series 1, 1, 1, 9.

Now multliply all the divisors that used in it i.e 2*3*5*2*9 = 540.

Gufran said:   1 decade ago
L.C.M
2 | 12,15,20,54
2 | 6 ,15,10,27
3 | 3 ,15,5 ,27
5 | 1 ,5 ,5 ,9
1 ,1 ,1 ,9
NOW,2*2*3*5*9=540
Required number = (L.C.M. of 12, 15, 20, 54) + 8

= 540 + 8

= 548.

Subhani said:   1 decade ago
Please anyone tell me what is the least natural number which when divided by 2, 3, 4, 5 or 6 leaves a remainder 1.

Umesh gupta said:   1 decade ago
L.C.M
2 | 2,3,4,5,6
2 | 1,3,2,5,3,
3 | 1,3,1,5,3
| 1,1,1,5,1

NOW,2*2*3*5=60
Required number = (L.C.M. of 2, 3, 4, 5 and 6) + 1

= 60 + 1

= 61

Disha said:   1 decade ago
After calculating the lcm why 8 is added?

Sreera said:   1 decade ago
Question is what is the number.

LCM OF 12, 15, 20 and 54 = 540.

Reminder = 8.

Exactly The Number is 540 + 8.


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