Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 25)
25.
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
504
536
544
548
Answer: Option
Explanation:

Required number = (L.C.M. of 12, 15, 20, 54) + 8

   = 540 + 8

   = 548.

Discussion:
30 comments Page 2 of 3.

Jalpan said:   1 decade ago
Can any one tell me. Why + ?

Why - not ?

Because I have seen some examples where, if HCF then taking remainder plus with dividend and if LCM then taking remainder substracted from the dividend. Explain please.

Ayesha said:   1 decade ago
Yes why it is not like 540k+8?

PKP said:   1 decade ago
Just divide all the answer options by 20 (because its easy) only option D leaves the remainder 8.

Sushma sharma said:   1 decade ago
Can two no. have 25 as their HCF answer 2034 as their LCM? Give reason in support of your answer?

Abdul said:   1 decade ago
Please explain the sum to me.

Shakti said:   1 decade ago
Yes why it is not 540k+8?
(1)

V!cky said:   10 years ago
2|12 15 20 54.
2|06 15 10 27.
3|03 15 05 27.
5|01 05 05 09.
9|01 01 01 09.
|01 01 01 01.

Best to find LCM solve till all value get 1.

You will always get perfect answer without confusion.

2*2*3*5*9 = 540.
(4)

V!cky said:   10 years ago
Just add remainder with it 540+8 = 548.

Vamsi said:   10 years ago
Some problem sub to remainder why please explain to me?

Anon said:   10 years ago
Shouldn't the answer be 8 here?


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