Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 25)
25.
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
504
536
544
548
Answer: Option
Explanation:

Required number = (L.C.M. of 12, 15, 20, 54) + 8

   = 540 + 8

   = 548.

Discussion:
30 comments Page 2 of 3.

Kinjal said:   10 years ago
Yes @Jalpan even I am confused as to when you need to subtract and when you need to add the remainder. Can anyone explain?

Ayush said:   7 years ago
Can anyone tell me what is the smallest number which when divided by 12, 20, 36 leaves no remainder?

Please answer it.

Sreera said:   1 decade ago
Question is what is the number.

LCM OF 12, 15, 20 and 54 = 540.

Reminder = 8.

Exactly The Number is 540 + 8.

Subhani said:   1 decade ago
Please anyone tell me what is the least natural number which when divided by 2, 3, 4, 5 or 6 leaves a remainder 1.

PKP said:   1 decade ago
Just divide all the answer options by 20 (because its easy) only option D leaves the remainder 8.

Sushma sharma said:   1 decade ago
Can two no. have 25 as their HCF answer 2034 as their LCM? Give reason in support of your answer?

Prannav said:   1 decade ago
Can anyone please show me the procedure to calculate the lcm as I think I am making some mistake.

Siva said:   6 years ago
@Fia.

The LCMof the number is 48 .plus add remainder 7 = 55.
Answer is 55.
(1)

Sharang Rane said:   9 years ago
Dividend = Divisor * Quotient + Remainder.

That's why +8.
(1)

Vamsi said:   10 years ago
Some problem sub to remainder why please explain to me?


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