Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)
4.
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Answer: Option
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Discussion:
158 comments Page 9 of 16.
Madhu said:
1 decade ago
Using successive division to find HCF of 1305,4665 and 6905 is 5
How it is 1120 ?
How it is 1120 ?
Surya said:
2 years ago
Why should we subtract the Numbers with the smallest number and so HCF for that?
(20)
Munsur said:
9 years ago
Will anyone explain the logic behind the Division Method of Finding HCF or GCD?
Gopika said:
8 years ago
@Saraswati.
I can't understand why you are multiplying 10?
Please explain it.
I can't understand why you are multiplying 10?
Please explain it.
Debita said:
9 years ago
@Srinivas.
Thanks, this is the perfect explanation like a true mathematician.
Thanks, this is the perfect explanation like a true mathematician.
Mehak said:
1 decade ago
Why we have to add 1+1+2+0? I'm not getting it. Please someone explain it.
Manish said:
1 decade ago
People try dividing each number by 8 and you will get the same remainder.
Suleman said:
1 decade ago
People try dividing each number by 8 and you will get the same remainder.
Bunny said:
9 years ago
Why should we subtract before finding out the HCF? can anybody tell me?
Haq ahmed said:
5 years ago
How we get the 1120 HCF of those number, can someone explain? please.
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