Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)
4.
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Answer: Option
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Discussion:
158 comments Page 8 of 16.
Chandra said:
1 decade ago
[(6905-1305)-(4665-1305)] / 2 = [2240] / 2 = 1120.
@Ravi can you explain how you did this step?
@Ravi can you explain how you did this step?
Bidya sagar behera said:
1 decade ago
I can't understand because of taking H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305).
Sudhanshu said:
9 years ago
Will you explain the below?
3360:2240:5600.
1120:1120:1120.
How we got this 1120 in common.
3360:2240:5600.
1120:1120:1120.
How we got this 1120 in common.
Swati said:
1 decade ago
Why we are taking the HCF of (4665 - 1305) , (6905 - 4665) and (6905 - 1305).
Plzzz explain.
Plzzz explain.
Princely said:
7 years ago
Can we try it in this way?
3+3+6+0= 12
2+2+4+0= 8,
5+6+0+0= 11,
12+8+11= 31,
3+1= 4.
3+3+6+0= 12
2+2+4+0= 8,
5+6+0+0= 11,
12+8+11= 31,
3+1= 4.
(1)
Sahid said:
1 decade ago
8 will divide each number and leave reminder 1, and 8 is greatest among all of the option.
Komathy said:
9 years ago
I Can't understand the N value, please explain the sum of digits N = (1 + 1 + 2 + 0) = 4?
Mukesh priye said:
10 years ago
Common no. of each row is 22227 & 10 hence multiple of that Product equal to 1120.
Gourav said:
2 years ago
@Anomi
Here, we need to find the greatest number. So 5 is not the greatest number.
Here, we need to find the greatest number. So 5 is not the greatest number.
(4)
Zara said:
1 decade ago
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4, how does it come and What N indicates?
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