Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)

Problems on H.C.F and L.C.M

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

Answer: Option

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Discussion:

158 comments Page 7 of 16.

J.manisha said: 1 decade ago

Sorry I can't understand this process. Please kindly give correct explanation. How will take this "N" value N = 1+1+2+0 = 4.

Sibaram said: 8 years ago

What if the question is for finding smallest such number? Is it same like we have to find lcm of difference between numbers?

Jayant Verma said: 8 years ago

8*163 = 1304 thus 1 remainder
583*8 = 4664 thus 1 remainder
863*8 = 6904 thus 1 remainder
So the answer should be 8.

(1)

Sumit said: 3 years ago

If we only take two differences i.e. 6905 - 4665 = 2240, 4665 - 1305 = 2360.
HCF of 2240 and 2360 is 40.
4+0 = 4.

(21)

Adarsha Gowda Mandya said: 1 decade ago

Hello @Sarswathi, why are you taking 10 to multiply number after the subtraction. Could you please tell me?

RAVI JAIN said: 1 decade ago

EASY ONE NO. ARE 6905, 4665, 1305

SO [(6905-1305)-(4665-1305)] / 2 = [2240] / 2 = 1120.

NOW 1+1+2+0 = 4.

Krishna kumar said: 1 decade ago

Sorry I can't understand why we are taking H. C. F. Of (4665 - 1305) , (6905 - 4665) and (6905 - 1305).

Ramana said: 1 decade ago

Thanks saraswathi. I get answer for this types of problems by following your explanation. Thanks a lot.

Suraj Chaudhary said: 2 years ago

I can't understand this question properly.

So, please If anybody knows properly it. Please explain it.

(13)

Ashwin said: 1 decade ago

Why are they finding H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) ?

Please explain.

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