Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)

Problems on H.C.F and L.C.M

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

Answer: Option

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Discussion:

158 comments Page 10 of 16.

Keerthi said: 1 decade ago

We have to find greatest num, hcf highest common factor.

So we did.

Anoop Singh said: 9 years ago

Anyone explain how the sum of digits in N = (1 + 1 + 2 + 0) = 4?

Moni Kumari said: 9 years ago

Thanks for this complete explanation @M. Harish and @Srinivas.

Sunny said: 1 decade ago

How would we know that H.C.F. of 3360, 2240 and 5600 = 1120.

(2)

YUVARAJ said: 1 decade ago

Hey please explain why we take hcf of 4665-1305, 6905-4665 ?

Merlinissac said: 12 months ago

4 * 1304 + 1 = 1305
4 * 4664 + 1 = 4665
4 * 6904 + 1 = 6905.

(3)

Nagarjuna D said: 1 decade ago

I can't understand why we have to subtract one among other?

Sai krishnan K said: 1 decade ago

Why it is not taken 5. It also gives the same remainder 0.

Renu said: 10 years ago

Hey can anyone tell how to find HCF fast for big numbers?

Sujit said: 1 decade ago

Why to take the difference between no.s? I don't get it.

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