Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 4)

Problems on H.C.F and L.C.M

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

Answer: Option

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

Discussion:

158 comments Page 11 of 16.

Nandhini said: 1 decade ago

Please can you explain how to calculate HCF and explain?

Dilz said: 8 years ago

Subtraction of these numbers cancels remainder but how?

Disha Mukherjee said: 4 months ago

I can't understand. Why should we subtract the numbers?

(15)

Rekha kharode said: 10 years ago

Please explain if someone knows why select only HCF?

Harini said: 6 years ago

@Anchit.

We should subtract remainder. i.e 12-2=10.

Elissa said: 4 years ago

I understood well, thanks to all for explaining.

(1)

Komal said: 3 years ago

Thank you for explaining the answer @Greeshma.

(2)

Agondeze milly said: 2 years ago

How do you get 4? I am not getting it clearly.

(13)

SWARNA said: 1 decade ago

How we know by seeing the numbers the H.C.F ?

Pallavi said: 1 decade ago

Please can you explain how to calculate HCF ?

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