Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 6 of 21.
Rajvir singh said:
1 decade ago
Why do need to take difference three times? (91-43), (183-91) was enough. and then take h.c.f. of 48 and 92 please someone give another example why do we need to do (183-43)?
Karthick said:
1 decade ago
@Cathy.
The keyword is greatest or largest- if you find these words, we are required to find HCF. If in case you find least or lowest in the problem, we need to find LCM.
The keyword is greatest or largest- if you find these words, we are required to find HCF. If in case you find least or lowest in the problem, we need to find LCM.
Anukriti srivastava said:
10 years ago
Is there any quick and efficient method to find HCF and LCM of big numbers such as HCF of 38094, 43762, 84632 for competitive exam if yes then please help me out waiting.
Honey said:
1 decade ago
Here 4 is even number. So its multiples will also be even. In the question above all the numbers were odd. If is divide by 4 then it will compulsory leaves an remainder.
Kumari said:
1 decade ago
Dear friends, Why they took difference between them and is any other easy as well as short method ? please communicate this answer as soon as possible. Thanking you.
M sai teja said:
1 decade ago
I think 43 and 91 are prime numbers.
Prime numbers don't have factors, to find H.C.F we need factors, for that we are subtracting numbers to get non-prime numbers.
Prime numbers don't have factors, to find H.C.F we need factors, for that we are subtracting numbers to get non-prime numbers.
Sowjanya said:
1 decade ago
Thanks prashanh, good explanation of sum, but I don't know some people are not at all trying to understand the topic first, then it is very easy my dear friends.
Chandu said:
10 years ago
1st divide 48 with 4 then remainder is 0.
2nd divide 92 with 4 then remainder is 0.
3rd divide 140 with 4 then remainder is 0.
Hence so 4 is a perfect number.
2nd divide 92 with 4 then remainder is 0.
3rd divide 140 with 4 then remainder is 0.
Hence so 4 is a perfect number.
Sandeep said:
1 decade ago
Why did we take the differences of the numbers?
Is this the only way to solve it by taking the differences if there is any other method then please reply?
Is this the only way to solve it by taking the differences if there is any other method then please reply?
Mahima Chaurasia said:
7 years ago
In the question it is asked the remainder should be same so, Answer is option A ie 4.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
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