Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 5 of 21.
Tamzid Khan said:
9 years ago
Is there anyone who will clearly explain why one has to take the difference of those numbers?
I mean what is the key note in the question seeing which I will solve the problem in this way?
Please explain someone.
I mean what is the key note in the question seeing which I will solve the problem in this way?
Please explain someone.
(1)
Ankur jindal said:
1 decade ago
If three nos as in this case is 43, 91 and 183 are given then to find HCF the shortest solution is take the diff:
1) 91 - 43 = 48 (4*3*7).
2) 183 - 91 = 92 (4*23).
3) 183 - 43 = 140 (4*7*5).
Thus the HCF is 4.
1) 91 - 43 = 48 (4*3*7).
2) 183 - 91 = 92 (4*23).
3) 183 - 43 = 140 (4*7*5).
Thus the HCF is 4.
Tahir said:
1 decade ago
Just simple according to the question there is no compilation is 43/4 the reminder is 3 then 91/4 the remainder is 3 and now 183/4 the reminder is once again three. F look at question the reminder is same ie 3.
Arya said:
1 decade ago
If three nos as in this case is 43, 91 and 183 are given then to find HCF the shortest solution is take the diff:
1) 91 - 43 = 48 (4*3*7)
2) 183 - 91 = 92 (4*23)
3) 183 - 43 = 140 (4*7*5)
Thus the HCF is 4.
1) 91 - 43 = 48 (4*3*7)
2) 183 - 91 = 92 (4*23)
3) 183 - 43 = 140 (4*7*5)
Thus the HCF is 4.
Anand said:
1 decade ago
No need to difference between them.
Simply take one by one option and divide given number in question (43, 91 and 183) and equate remainder.
No need to difference between them. Okay friends. So simple !
Simply take one by one option and divide given number in question (43, 91 and 183) and equate remainder.
No need to difference between them. Okay friends. So simple !
Ranjeet said:
1 decade ago
Simply because there is no same factor of these no and they don't divide by each other when we divide 91 by 43 there remainder is 5 that is not the divisible of 43. So we take this method to explanation.
Heena said:
1 decade ago
Here take the difference between the numbers then start dividing.
48/2, 92/2, 140/2
Then
48/2=2*2*2*2*3
92/2=2*2*23
140/2=2*2*35
So HCF is [nothing but the highest common factor].
So HCFis 2*2=4.
48/2, 92/2, 140/2
Then
48/2=2*2*2*2*3
92/2=2*2*23
140/2=2*2*35
So HCF is [nothing but the highest common factor].
So HCFis 2*2=4.
Nirmod Kumar Mandal said:
2 years ago
Subtract the smallest number from both the highest numbers.
We have three cases:
183 > 43; 183 > 91 and 91 > 43.
183 - 43 = 140,
183 - 91 = 92 and,
91 - 43 = 48.
Why? Please explain.
We have three cases:
183 > 43; 183 > 91 and 91 > 43.
183 - 43 = 140,
183 - 91 = 92 and,
91 - 43 = 48.
Why? Please explain.
(31)
Pkhoche said:
2 months ago
43, 91, 183 :
Solution by Factorisation:
The factors of 43 are: 1, 43.
The factors of 91 are: 1, 7, 13, 91.
The factors of 183 are: 1, 3, 61, 183.
Then the greatest common factor is 1.
Solution by Factorisation:
The factors of 43 are: 1, 43.
The factors of 91 are: 1, 7, 13, 91.
The factors of 183 are: 1, 3, 61, 183.
Then the greatest common factor is 1.
(13)
Vinitha said:
1 decade ago
Hey friends.
H.C.F. of (91-43=48), (183-91=92), (183-43=140).
H.C.F. of 48, 92, 140 = 4.
48 = 4*12,
92 = 4*23,
140 = 4*35.
So we divided by 4 in all 48, 92, 140.
Thus H.C.F. is 4.
H.C.F. of (91-43=48), (183-91=92), (183-43=140).
H.C.F. of 48, 92, 140 = 4.
48 = 4*12,
92 = 4*23,
140 = 4*35.
So we divided by 4 in all 48, 92, 140.
Thus H.C.F. is 4.
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