Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
214 comments Page 7 of 22.
Sandeep said:
1 decade ago
Why did we take the differences of the numbers?
Is this the only way to solve it by taking the differences if there is any other method then please reply?
Is this the only way to solve it by taking the differences if there is any other method then please reply?
Mahima Chaurasia said:
8 years ago
In the question it is asked the remainder should be same so, Answer is option A ie 4.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
Akshta said:
6 years ago
Do we know the number no let's assume the number is X therefore 43/X = 4 ithr for 43-4= 40 and similar to the all and by dividing we get reminder as 4.
Dhananjay said:
1 decade ago
@ Sanddep:
Have a look at explanation given by @Prasant. We have to solve equation for 'p'. Hence,we eliminate 'r' by taking differences of numbers.
Have a look at explanation given by @Prasant. We have to solve equation for 'p'. Hence,we eliminate 'r' by taking differences of numbers.
Chirag said:
1 decade ago
Easy calculation, 7 and 13 are directly eliminated.
4 and 9 are the required. So divide it by the 9, no remainder will be same. So 4 is the option.
4 and 9 are the required. So divide it by the 9, no remainder will be same. So 4 is the option.
Ajeeth said:
10 years ago
How to take HCF I don't know how to take HCF please anybody explains me. How to find the HCF for any unknowns for ex: 533, 522, 455 for this number?
Bala said:
7 years ago
@All.
They asked to divide by a number also we need to have the same remainder in all cases.
So, dividing by 4, we get remainder 3 in all cases.
They asked to divide by a number also we need to have the same remainder in all cases.
So, dividing by 4, we get remainder 3 in all cases.
(1)
Mayank said:
1 decade ago
4*22-gives rem 3.
4*10-gives rem3.
4*45-also gives rem 3.
All three numbers have equal rem 3 satisfies condition given in number. Hence ans is 4.
4*10-gives rem3.
4*45-also gives rem 3.
All three numbers have equal rem 3 satisfies condition given in number. Hence ans is 4.
Mini said:
1 decade ago
Why they took the differences of given 3 numbers and then calculated the H.C.F.
Why didn't they simply calculate the H.C.F OF GIVEN 3 NUMBERS.
Why didn't they simply calculate the H.C.F OF GIVEN 3 NUMBERS.
Mr.newton said:
10 years ago
Everything is fine, but I am getting doubt with HCF. In three numbers common we get 2. If we divided 2 * 2 * 2 get 8. Why are you telling 4?
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