Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 7 of 21.
Akshta said:
5 years ago
Do we know the number no let's assume the number is X therefore 43/X = 4 ithr for 43-4= 40 and similar to the all and by dividing we get reminder as 4.
Dhananjay said:
1 decade ago
@ Sanddep:
Have a look at explanation given by @Prasant. We have to solve equation for 'p'. Hence,we eliminate 'r' by taking differences of numbers.
Have a look at explanation given by @Prasant. We have to solve equation for 'p'. Hence,we eliminate 'r' by taking differences of numbers.
Chirag said:
10 years ago
Easy calculation, 7 and 13 are directly eliminated.
4 and 9 are the required. So divide it by the 9, no remainder will be same. So 4 is the option.
4 and 9 are the required. So divide it by the 9, no remainder will be same. So 4 is the option.
Ajeeth said:
9 years ago
How to take HCF I don't know how to take HCF please anybody explains me. How to find the HCF for any unknowns for ex: 533, 522, 455 for this number?
Bala said:
6 years ago
@All.
They asked to divide by a number also we need to have the same remainder in all cases.
So, dividing by 4, we get remainder 3 in all cases.
They asked to divide by a number also we need to have the same remainder in all cases.
So, dividing by 4, we get remainder 3 in all cases.
(1)
Mayank said:
1 decade ago
4*22-gives rem 3.
4*10-gives rem3.
4*45-also gives rem 3.
All three numbers have equal rem 3 satisfies condition given in number. Hence ans is 4.
4*10-gives rem3.
4*45-also gives rem 3.
All three numbers have equal rem 3 satisfies condition given in number. Hence ans is 4.
Mini said:
1 decade ago
Why they took the differences of given 3 numbers and then calculated the H.C.F.
Why didn't they simply calculate the H.C.F OF GIVEN 3 NUMBERS.
Why didn't they simply calculate the H.C.F OF GIVEN 3 NUMBERS.
Mr.newton said:
9 years ago
Everything is fine, but I am getting doubt with HCF. In three numbers common we get 2. If we divided 2 * 2 * 2 get 8. Why are you telling 4?
Kanchan said:
1 decade ago
As it is asking for greatest no among all options the answer for above problem should be 7 as it divides all the no and gives remainder 0.
Merry said:
1 decade ago
When pratibhan said the common factor is 2 ok this is write but why she multiple two no of 2 whyn't three no of 2 means the result is 8.
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