Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 8 of 21.
Ankush said:
7 years ago
@Mrunmay.
Solution they take difference because to make remainder zero. And than that divisor will divine these number Completely.
Solution they take difference because to make remainder zero. And than that divisor will divine these number Completely.
Davoas said:
7 years ago
What if we have a fixed remainder.
For example take 90, 114 and 230 with remainder 6 what will be the divisor?
Anyone explain me.
For example take 90, 114 and 230 with remainder 6 what will be the divisor?
Anyone explain me.
Rajesh said:
1 decade ago
1.91-43 = 48, 183-91 = 92, 183-43 = 140.
2.92-48 = 44, 140-92 = 48, 140-48 = 92.
For every time we eliminating uncommon Factors.
2.92-48 = 44, 140-92 = 48, 140-48 = 92.
For every time we eliminating uncommon Factors.
Trishana said:
10 years ago
Here in this question greatest number is 7 and it gives the same remainder that is 1 when divided by all. So how is the answer 4?
Shital said:
1 decade ago
Mysterious please tell me how will be that example converted if divide method and factorization method has given in example?
Dhanasekar said:
1 decade ago
Can any one explain how to identify. Whether the problem is based on HCF or least common multiple. Is there any key words?
Sixface said:
7 years ago
It's very simple guys =>
43/4=3,
92/4=3,
183/4=3.
The remainder is 3 for all divide so 4 is the correct answer.
43/4=3,
92/4=3,
183/4=3.
The remainder is 3 for all divide so 4 is the correct answer.
Madhu said:
3 years ago
Take difference:
43 - 91 = 48.
91 - 183 = 92,
Now take the hcf of difference numbers 49, 92.
The HCF Of 48, 92 = 40.
43 - 91 = 48.
91 - 183 = 92,
Now take the hcf of difference numbers 49, 92.
The HCF Of 48, 92 = 40.
(19)
Aditya said:
1 decade ago
Find the least number divisible by 12, 32, 42, and 63 and it must be a perfect square?
Please give me the solution.
Please give me the solution.
Phani said:
9 years ago
Is this the common HCF problem if so when I try to solve it using Euclid's method I got the answer '1'.
Am I right?
Am I right?
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