Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)

Problems on H.C.F and L.C.M

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Answer: Option

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Discussion:

212 comments Page 21 of 22.

G vinay said: 8 years ago

How? Please explain the answer.

Ishaq said: 4 years ago

Thanks everyone for explaining.

Sayyidah shah said: 8 years ago

Best solution, Thanks @Nikita.

Navneet said: 1 decade ago

Divide each with each option.

Palguni said: 1 year ago

Good explanation. Thanks all.

(15)

Alex said: 9 years ago

Good explanation @Prashant.

Thilak said: 6 years ago

Thanks for the explanation.

Ashish saini said: 1 decade ago

Thanks my dear parshant.

Lokesh said: 6 years ago

Why we have to use hcf?

Chaitanya said: 1 decade ago

How to calculate HCF ?

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