Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)

Problems on H.C.F and L.C.M

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Answer: Option

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Discussion:

210 comments Page 20 of 21.

Lakshmisha said: 1 decade ago

@Prashant, thanks for explanation

Sowmya said: 8 years ago

Well explained, thanks @Prashant.

Prathyusha said: 1 decade ago

SMART WAY OF SOLVING BY @SHWETHA

NARESH said: 1 decade ago

Please explain again simply way.

Daniel said: 9 years ago

I can't understand the question.

Narendra Singh said: 4 years ago

Thanks everyone for explaianing.

(4)

Bhakti said: 5 months ago

Good explanation, Thank you all.

(4)

Lohit said: 1 decade ago

Explain logic of the solution ?

G vinay said: 7 years ago

How? Please explain the answer.

Ishaq said: 4 years ago

Thanks everyone for explaining.

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