Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)

Problems on H.C.F and L.C.M

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Answer: Option

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Discussion:

216 comments Page 20 of 22.

Mahima said: 8 years ago

Nice explanation @Parthiban. Thanks.

Vishakha said: 2 months ago

Thanks everyone for explaining this.

(1)

Anu said: 2 decades ago

Explain the logic of this solution.

Krishna said: 2 decades ago

4*3*7 is wrong right one is 4*12 k

Hapreet said: 1 decade ago

Why we have to less these numbers?

Pooja Madrewar said: 1 decade ago

Explain the logic of this solution

Lakshmisha said: 1 decade ago

@Prashant, thanks for explanation

Sowmya said: 9 years ago

Well explained, thanks @Prashant.

Prathyusha said: 2 decades ago

SMART WAY OF SOLVING BY @SHWETHA

NARESH said: 1 decade ago

Please explain again simply way.

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