Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)

Problems on H.C.F and L.C.M

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Answer: Option

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Discussion:

210 comments Page 19 of 21.

Gowtham said: 8 years ago

Thanks @Komal.

I could finally get it.

Piyush said: 3 years ago

Best Answer, well said, Thanks @Logesh.

(36)

Ajit said: 1 decade ago

Thanks prashant for best explanation.

Darshil said: 4 years ago

Why they subtracted? Explain, please.

Manjunath said: 10 years ago

I want the explanation of the logic.

Mahima said: 8 years ago

Nice explanation @Parthiban. Thanks.

Anu said: 2 decades ago

Explain the logic of this solution.

Krishna said: 1 decade ago

4*3*7 is wrong right one is 4*12 k

Hapreet said: 1 decade ago

Why we have to less these numbers?

Pooja Madrewar said: 1 decade ago

Explain the logic of this solution

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