Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)

Problems on H.C.F and L.C.M

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Answer: Option

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Discussion:

212 comments Page 18 of 22.

Aravind B said: 5 years ago

Thanks all for giving the clear explanation.

Lakhan saini said: 1 decade ago

Divided by 4 each number we get remainder 3

Shi said: 8 months ago

This is good to gain knowledge. Thanks all.

(8)

Aadhilakshmi said: 1 decade ago

Thanks for the clear explanation prasanth.

Ram rao said: 4 years ago

Thanks everyone for explaining the answer.

(3)

R. Ahmad said: 1 decade ago

Why it is used two times 183 nos Explain?

Surbhi swaraj said: 1 decade ago

Is there any trick to solve this problem?

Mz Gucchi said: 10 years ago

Hi, how to solve the Lcm? Please help me.

Tanvi said: 9 years ago

I am not understanding please explain me.

Pavi said: 3 years ago

Thanks all for the detailed explanation.

(63)

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