Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)

Problems on H.C.F and L.C.M

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Answer: Option

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Discussion:

214 comments Page 17 of 22.

Sandeep.ch said: 1 decade ago

Please tell me which is the perfect explanation.

Afsa said: 1 decade ago

Some one help! What is the logic behind H. C. F?

Rocky said: 5 months ago

If any one number is prime, then HCF will be 1.

(11)

Titus said: 2 decades ago

That is true. Understanding is more important.

Suganthy said: 1 decade ago

Thanks for all who have explained the concept.

Magnus Udoka said: 7 years ago

Your explanation was superb, Thanks @Prashant.

Pabitra Saha said: 7 years ago

Very good explanation, Thanks @Kuldeep Sharma.

Lavan said: 1 decade ago

Why we have to take difference of two number?

Jyothi said: 8 years ago

Not getting it, can anyone please explain it?

Chary said: 8 years ago

Thanks for giving nice explanation @Prasanth.

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