Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)

Problems on H.C.F and L.C.M

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Answer: Option

Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

Discussion:

210 comments Page 17 of 21.

Suganthy said: 1 decade ago

Thanks for all who have explained the concept.

Magnus Udoka said: 7 years ago

Your explanation was superb, Thanks @Prashant.

Pabitra Saha said: 6 years ago

Very good explanation, Thanks @Kuldeep Sharma.

Lavan said: 1 decade ago

Why we have to take difference of two number?

Jyothi said: 8 years ago

Not getting it, can anyone please explain it?

Chary said: 7 years ago

Thanks for giving nice explanation @Prasanth.

Mandeep said: 1 decade ago

@Prashant.

P is not a dividend its divisor.

SHYAM YADAV said: 9 years ago

What are the numbers to find the difference?

Aravind B said: 4 years ago

Thanks all for giving the clear explanation.

Lakhan saini said: 1 decade ago

Divided by 4 each number we get remainder 3

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