Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
213 comments Page 17 of 22.
Afsa said:
1 decade ago
Some one help! What is the logic behind H. C. F?
Rocky said:
3 months ago
If any one number is prime, then HCF will be 1.
(5)
Titus said:
2 decades ago
That is true. Understanding is more important.
Suganthy said:
1 decade ago
Thanks for all who have explained the concept.
Magnus Udoka said:
7 years ago
Your explanation was superb, Thanks @Prashant.
Pabitra Saha said:
7 years ago
Very good explanation, Thanks @Kuldeep Sharma.
Lavan said:
1 decade ago
Why we have to take difference of two number?
Jyothi said:
8 years ago
Not getting it, can anyone please explain it?
Chary said:
8 years ago
Thanks for giving nice explanation @Prasanth.
Mandeep said:
1 decade ago
@Prashant.
P is not a dividend its divisor.
P is not a dividend its divisor.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers