Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
4
7
9
13
Answer: Option
Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

     = H.C.F. of 48, 92 and 140 = 4.

Discussion:
210 comments Page 4 of 21.

Sandeep.ch said:   1 decade ago
Please tell me which is the perfect explanation.

Abhishek said:   1 decade ago
@Prashant: thanks for best explanation.

Ajit said:   1 decade ago
Thanks prashant for best explanation.

Nadhirsha said:   1 decade ago
Well done Prashant.

Samir said:   1 decade ago
Which is the highest five digit number which is equally divisible by 60, 80, and 90 and how to arrive this answer ?

Hapreet said:   1 decade ago
Why we have to less these numbers?

Ranjeet said:   1 decade ago
Simply because there is no same factor of these no and they don't divide by each other when we divide 91 by 43 there remainder is 5 that is not the divisible of 43. So we take this method to explanation.

Uzair said:   1 decade ago
U guys are not understanding the meaning of H.C.F actually...i'll give an example and an explanation!
Highest common factor
Here are the list of prime factors of 24 and 36:
24 = 2 x 2 x 2 x 3
36 = 2 x 2 x 3 x 3
If we write down the numbers that are the same in both lists, they will give us the highest common factor of 24 and 36:
HCF of 24 and 36 is 2 x 2 x 3 = 12
This is the meaning of H.C.F...so simple! :D

Ashish saini said:   1 decade ago
Thanks my dear parshant.

Sowjanya said:   1 decade ago
Thanks prashanh, good explanation of sum, but I don't know some people are not at all trying to understand the topic first, then it is very easy my dear friends.


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