Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
213 comments Page 22 of 22.
Anup said:
4 months ago
Why need to subtract and generate a new number, then take hcf ? Anyone, please explain to me.
(10)
Rocky said:
3 months ago
If any one number is prime, then HCF will be 1.
(5)
Rudra Prasad Lenka said:
2 weeks ago
1st you have to subtract them all by each higher no.
(183-43) = 140.
(183-91) = 92.
(91-43) = 48.
Now find the common factor of these new numbers.
i.e 4.
So the correct answer is option A.
(183-43) = 140.
(183-91) = 92.
(91-43) = 48.
Now find the common factor of these new numbers.
i.e 4.
So the correct answer is option A.
(2)
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