Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
214 comments Page 22 of 22.
Anup said:
5 months ago
Why need to subtract and generate a new number, then take hcf ? Anyone, please explain to me.
(17)
Rocky said:
5 months ago
If any one number is prime, then HCF will be 1.
(11)
Rudra Prasad Lenka said:
2 months ago
1st you have to subtract them all by each higher no.
(183-43) = 140.
(183-91) = 92.
(91-43) = 48.
Now find the common factor of these new numbers.
i.e 4.
So the correct answer is option A.
(183-43) = 140.
(183-91) = 92.
(91-43) = 48.
Now find the common factor of these new numbers.
i.e 4.
So the correct answer is option A.
(6)
SHEHREEN KAUR said:
12 hours ago
@All.
Why do we subtract?
Because if a number leaves the same remainder, then the differences between the numbers are divisible by that number.
Now, the numbers obtained after subtraction are divisible by their HCF or GCD.
So, after prime factorisation, the HCF is 4.
Why do we subtract?
Because if a number leaves the same remainder, then the differences between the numbers are divisible by that number.
Now, the numbers obtained after subtraction are divisible by their HCF or GCD.
So, after prime factorisation, the HCF is 4.
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