Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 3 of 21.
JAYALALITHA said:
1 decade ago
WHY WE HAVE TO TAKE DIFFERENCE OF THOSE TWO NUMBERS
Prathyusha said:
1 decade ago
SMART WAY OF SOLVING BY @SHWETHA
Yuva kumar said:
1 decade ago
Dear Sir/madam please expain I could not understand.
R. Ahmad said:
1 decade ago
Why it is used two times 183 nos Explain?
Fil said:
1 decade ago
If you mult 4*3*7 its coming 84 how 4 will be the greatest no please explain me.
Krishna said:
1 decade ago
4*3*7 is wrong right one is 4*12 k
Vidhya said:
1 decade ago
Why we have to take the difference of those two numbers?
Sita said:
1 decade ago
I'm not clear with any of the above explanation. Can anyone tell me clearly.
Mini said:
1 decade ago
Why they took the differences of given 3 numbers and then calculated the H.C.F.
Why didn't they simply calculate the H.C.F OF GIVEN 3 NUMBERS.
Why didn't they simply calculate the H.C.F OF GIVEN 3 NUMBERS.
Mysterious said:
1 decade ago
@Mini and all friends
If it was just asked to find the HCF of 43,91,183 then simply the Division method or Factorization method had been applied.
But here it is stated that "so as to leave the same remainder in each case", that's why the difference of the numbers is calculated.
If it was just asked to find the HCF of 43,91,183 then simply the Division method or Factorization method had been applied.
But here it is stated that "so as to leave the same remainder in each case", that's why the difference of the numbers is calculated.
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