Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 20 of 21.
G vinay said:
7 years ago
How? Please explain the answer.
Ahmad Zaidi said:
7 years ago
@Samir.
First find the LCM of 60, 80, 90, which is 720. Then divide it by 99999 which is highest 5 digit number, and less the reminder which is 639 and answer is 99360. Which is equally divisible by 60, 80, 90. Thanks.
First find the LCM of 60, 80, 90, which is 720. Then divide it by 99999 which is highest 5 digit number, and less the reminder which is 639 and answer is 99360. Which is equally divisible by 60, 80, 90. Thanks.
Chary said:
7 years ago
Thanks for giving nice explanation @Prasanth.
Sixface said:
7 years ago
It's very simple guys =>
43/4=3,
92/4=3,
183/4=3.
The remainder is 3 for all divide so 4 is the correct answer.
43/4=3,
92/4=3,
183/4=3.
The remainder is 3 for all divide so 4 is the correct answer.
Shanmukh Adari said:
7 years ago
Your explanation is fantastic, Thank you so much @Prashant.
Mahima Chaurasia said:
7 years ago
In the question it is asked the remainder should be same so, Answer is option A ie 4.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
Pabitra Bhusan Saha said:
7 years ago
Your explanation is very easy to understand and this is the best process, Thanks @Saroja and @Sourav.
Magnus Udoka said:
7 years ago
Your explanation was superb, Thanks @Prashant.
Davoas said:
7 years ago
What if we have a fixed remainder.
For example take 90, 114 and 230 with remainder 6 what will be the divisor?
Anyone explain me.
For example take 90, 114 and 230 with remainder 6 what will be the divisor?
Anyone explain me.
Pabitra Saha said:
6 years ago
Very good explanation, Thanks @Kuldeep Sharma.
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