Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
4
7
9
13
Answer: Option
Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

     = H.C.F. of 48, 92 and 140 = 4.

Discussion:
210 comments Page 21 of 21.

Pinku said:   6 years ago
43/4 = 3(remainder).
91/4 = 3(remainder).
183/4 = 3(remainder).

Lokesh said:   6 years ago
Why we have to use hcf?

Akshta said:   5 years ago
Do we know the number no let's assume the number is X therefore 43/X = 4 ithr for 43-4= 40 and similar to the all and by dividing we get reminder as 4.

Thilak said:   5 years ago
Thanks for the explanation.

Nic said:   5 years ago
Same remainder means? Please anyone explain for me.

Tejveer said:   5 years ago
@Karthik V.

Great explanation, Thanks for solving this.

Sakthi said:   5 years ago
Why they took difference here? Anyone explain about it.

Aravind B said:   4 years ago
Thanks all for giving the clear explanation.

Darshil said:   4 years ago
Why they subtracted? Explain, please.

Ishaq said:   4 years ago
Thanks everyone for explaining.


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