Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
216 comments Page 21 of 22.
Mahima Chaurasia said:
8 years ago
In the question it is asked the remainder should be same so, Answer is option A ie 4.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
43/4 remainder is 03.
91/4 remainder is 03.
183/4 remainder is 03.
Pabitra Bhusan Saha said:
8 years ago
Your explanation is very easy to understand and this is the best process, Thanks @Saroja and @Sourav.
Magnus Udoka said:
7 years ago
Your explanation was superb, Thanks @Prashant.
Davoas said:
7 years ago
What if we have a fixed remainder.
For example take 90, 114 and 230 with remainder 6 what will be the divisor?
Anyone explain me.
For example take 90, 114 and 230 with remainder 6 what will be the divisor?
Anyone explain me.
Pabitra Saha said:
7 years ago
Very good explanation, Thanks @Kuldeep Sharma.
Pinku said:
7 years ago
43/4 = 3(remainder).
91/4 = 3(remainder).
183/4 = 3(remainder).
91/4 = 3(remainder).
183/4 = 3(remainder).
Lokesh said:
7 years ago
Why we have to use hcf?
Akshta said:
6 years ago
Do we know the number no let's assume the number is X therefore 43/X = 4 ithr for 43-4= 40 and similar to the all and by dividing we get reminder as 4.
Thilak said:
6 years ago
Thanks for the explanation.
Nic said:
5 years ago
Same remainder means? Please anyone explain for me.
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