Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
4
7
9
13
Answer: Option
Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

     = H.C.F. of 48, 92 and 140 = 4.

Discussion:
216 comments Page 19 of 22.

Sowmya said:   9 years ago
Well explained, thanks @Prashant.

Mani said:   9 years ago
Why can't we think like this, In given four option one is HCF of 43, 91, 183. And leave the same reminder as per the question.

Let me consider 4 is HCF then divide the numbers by four. It shows the same reminder hence 4 is the answer.

STUTI said:   9 years ago
I understood the sum now.

Given explanations was good. Thankyou all.

Rituraj said:   9 years ago
Well done @Saurabh.

Lokesh said:   9 years ago
Easy to understand. Thanks to all the given explanation.

Alex said:   9 years ago
Good explanation @Prashant.

Mohan said:   9 years ago
Hi.

In question, they gave a greatest number, in the sense.

Ex- if you take 4 as a greater num for the given question.

Means this is the greater num which divides all the dividend if you take 5 it won't divide all' the dividends.

If they ask greater num -then take smaller num in the choices and divide all the dividends by that num if you get remainder same then that is the answer.

Rajat said:   9 years ago
Why we taking the difference between these, first explain this.

Gowtham said:   9 years ago
Thanks @Komal.

I could finally get it.

Sayyidah shah said:   8 years ago
Best solution, Thanks @Nikita.


Post your comments here:

Your comments will be displayed after verification.