Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 16)
16.
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:
Answer: Option
Explanation:
Other number = | ![]() |
11 x 7700 | ![]() |
= 308. |
275 |
Discussion:
21 comments Page 2 of 3.
Pavan said:
7 years ago
Its formula is;
The product of two numbers=H.C.F * L.C.M.
The product of two numbers=H.C.F * L.C.M.
Savitha said:
1 decade ago
Is there any formula for this kind of problems ?
Priya said:
1 decade ago
HCF is included in LCM then why 11*7700/275?
Jatin said:
1 decade ago
This is a right formula to write the answer.
Sougandhika said:
7 years ago
Why we can't do like this 11a*11b=7700?
(3)
Ramya said:
1 decade ago
Why we have to multiply 11 and 7700?
Syed said:
1 decade ago
Good and easy way to answer praveen
K.mauri said:
7 years ago
What is the HFC of 77 and 275?
(1)
Sampath said:
2 years ago
Thanks for explaining @kush.
(2)
Pretty said:
8 years ago
Thanks for the explanation.
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