Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 16)
16.
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:
Answer: Option
Explanation:
| Other number = |  |
11 x 7700 |  |
= 308. |
| 275 |
Discussion:
21 comments Page 1 of 3.
Praveen said:
1 decade ago
It can also be solve like this. By considering options only option C is dividing by 11.
Ramya said:
1 decade ago
Why we have to multiply 11 and 7700?
Savitha said:
1 decade ago
Is there any formula for this kind of problems ?
Raju said:
1 decade ago
IF only HCF & LCM is given then how to find numbers.
eg: If 24 & 720 is HCF & LCM of TWO numbers respectively,find the numbers
eg: If 24 & 720 is HCF & LCM of TWO numbers respectively,find the numbers
(1)
Syed said:
1 decade ago
Good and easy way to answer praveen
Kush said:
1 decade ago
This type of problem can be solved by a formula:
LCM X HCF = First No. X Second No.
Here
LCM=7700
HCF=11
First No.=275
7700 X 11 = 275 X Second No.
Second No.= 308
LCM X HCF = First No. X Second No.
Here
LCM=7700
HCF=11
First No.=275
7700 X 11 = 275 X Second No.
Second No.= 308
Trinath said:
1 decade ago
Let 2 no's with H.C.F 11 are 11x and 11y.
One of the numbers is 275.
L.C.M of 275 and 11y is 275y.
Given L.C.M = 7700.
275y = 7700 => y = 28.
Therefore another number=11*y = 11*28 =308.
One of the numbers is 275.
L.C.M of 275 and 11y is 275y.
Given L.C.M = 7700.
275y = 7700 => y = 28.
Therefore another number=11*y = 11*28 =308.
Sushank said:
1 decade ago
Other number = H.C.F.* L.C.M/Given No.
= 11*7700/275
= 84700/275
= 308
Hence, the other number is 308.
= 11*7700/275
= 84700/275
= 308
Hence, the other number is 308.
Priya said:
1 decade ago
HCF is included in LCM then why 11*7700/275?
Prini said:
1 decade ago
It is based on formula,
Product of two nos = product of their HCF and LCM.
Refer important formula (4).
Product of two nos = product of their HCF and LCM.
Refer important formula (4).
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