Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 16)
16.
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:
279
283
308
318
Answer: Option
Explanation:
Other number = 11 x 7700 = 308.
275
Discussion:
21 comments Page 1 of 3.

Manshi said:   4 years ago
There is a formula for this,

HCF * LCM = first no * second no.
(7)

Chaitanya said:   5 years ago
Their is a formula i.e,
a*b=HCF*LCM.

here they have given one number i.e275 so u can take a=275 or b=275.
Hence substitute in the above formula,
a*275=11*7700,
a=11*7700/275,
a=308.
(3)

Sougandhika said:   7 years ago
Why we can't do like this 11a*11b=7700?
(3)

Sampath said:   2 years ago
Thanks for explaining @kush.
(2)

Maddy said:   8 years ago
The numbers are 11x, 11y.

LCM of two numbers x * 11* y
Therefore x * 11 * y = 7700.
11x = 275,
ie., 275 * y = 7700,
y = 28,

The other number is 11*y => 11*28 => 308.
(2)

Raju said:   1 decade ago
IF only HCF & LCM is given then how to find numbers.

eg: If 24 & 720 is HCF & LCM of TWO numbers respectively,find the numbers
(1)

K.mauri said:   7 years ago
What is the HFC of 77 and 275?
(1)

Jatin said:   1 decade ago
This is a right formula to write the answer.

Pavan said:   7 years ago
Its formula is;

The product of two numbers=H.C.F * L.C.M.

Pretty said:   8 years ago
Thanks for the explanation.


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