Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 22)
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
Answer: Option
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
First number = | ![]() |
551 | ![]() |
= 19; Third number = | ![]() |
1073 | ![]() |
= 37. |
29 | 29 |
Required sum = (19 + 29 + 37) = 85.
Discussion:
53 comments Page 4 of 6.
Prasant said:
1 decade ago
How to find 29 ? Is there any shortest way?
Priya said:
4 years ago
Really Awesome explanation, Thanks @Aparna.
(2)
Rudrika said:
9 years ago
@Ashutosh,
Your explanation is very nice.
Your explanation is very nice.
Mouni said:
4 years ago
HCF of 551 and 1073 = 29 + 19 + 27 = 85.
Mahi said:
9 years ago
Good and clear explanation @Ashutosh.
Samir said:
9 years ago
Why we divide 29 from 551 & 1073?
Soni said:
9 years ago
Please, explain the problem clearly.
Krishna said:
9 years ago
@Jyoti, Can you explain it clearly?
Anvi said:
4 years ago
Why we use HCF ? Explain clearly.
(3)
Kalpit said:
7 years ago
Good explanatiion, Thanks @Uttam.
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