Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 22)
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
Answer: Option
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
First number = | ![]() |
551 | ![]() |
= 19; Third number = | ![]() |
1073 | ![]() |
= 37. |
29 | 29 |
Required sum = (19 + 29 + 37) = 85.
Discussion:
53 comments Page 3 of 6.
Rahul said:
1 decade ago
Can any one tell me how to calculate HCF/LCM of big numbers in easy way?
Anonymous said:
9 years ago
How will the solution change if the given numbers are not co-prime?
Riteeka said:
4 years ago
Hey @Satyajit.
Your method is perfect. Helped a lot. Thank you.
Your method is perfect. Helped a lot. Thank you.
(2)
Sangeeta said:
1 decade ago
How to know that 29 is the common factor?
Please tell me?
Please tell me?
Venkatareddy said:
1 decade ago
How the you can say 29 is the common factor and explain?
Shreya said:
6 years ago
I don't understand why we take the HCF of 551 and 1073.
(6)
Anjali said:
1 decade ago
I didn't understand this question. Please help me.
Mustafa Ahmed said:
1 decade ago
How to find 29? Please show the divided process.
Tanu said:
7 years ago
Why we take HCF why not LCM? Please explain me.
Priya said:
4 years ago
Really Awesome explanation, Thanks @Aparna.
(2)
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