Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 22)
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
Answer: Option
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
| First number = |  |
551 |  |
= 19; Third number = | |
1073 | |
= 37. |
| 29 | 29 |
Required sum = (19 + 29 + 37) = 85.
Discussion:
53 comments Page 4 of 6.
Uttam said:
1 decade ago
Consider numbers as X, Y, Z respectively.
Now,
Consider product XY = 551 ------eq1
Consider product YZ = 1073 -----eq2
So,clearly common highest factor btw XY and YZ should be Y
i.e HCF (551,1073) = 29.
From eq 1, X=19.
from eq 2, Y=37.
Pls comment if my assumption is wrong.
Now,
Consider product XY = 551 ------eq1
Consider product YZ = 1073 -----eq2
So,clearly common highest factor btw XY and YZ should be Y
i.e HCF (551,1073) = 29.
From eq 1, X=19.
from eq 2, Y=37.
Pls comment if my assumption is wrong.
Vinayak said:
1 decade ago
@uttam. You are right.
Sangeeta said:
1 decade ago
How to know that 29 is the common factor?
Please tell me?
Please tell me?
Prasant said:
1 decade ago
How to find 29 ? Is there any shortest way?
Ashutosh said:
1 decade ago
Hello friends its simple to get 29.
1 step:-1073-551 we will get 522.
Now,
2 step:- 551-522 we will get 29
1 step:-1073-551 we will get 522.
Now,
2 step:- 551-522 we will get 29
Rahul said:
1 decade ago
Can any one tell me how to calculate HCF/LCM of big numbers in easy way?
Mustafa Ahmed said:
1 decade ago
How to find 29? Please show the divided process.
Gopi said:
1 decade ago
In-case of co primes, if 29 is the middle number then first should be 23 and last should be 31. Then the given values not match. Please clarify.
Venkatareddy said:
1 decade ago
How the you can say 29 is the common factor and explain?
Prathyusha.j said:
1 decade ago
@Gopi.
If we take the numbers to be 23 and 31,
We get 23*29=667.. which is in contrast with the question.
So the numbers should be 19 and 37.
If we take the numbers to be 23 and 31,
We get 23*29=667.. which is in contrast with the question.
So the numbers should be 19 and 37.
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