Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 22)
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
Answer: Option
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
First number = | ![]() |
551 | ![]() |
= 19; Third number = | ![]() |
1073 | ![]() |
= 37. |
29 | 29 |
Required sum = (19 + 29 + 37) = 85.
Discussion:
53 comments Page 6 of 6.
Anant said:
9 years ago
Thanks @Ashutosh.
Preethi said:
9 years ago
I can't understand how 29 comes?
Ram said:
9 years ago
29 is the HCF of 551 and 1073.
To find HCF of 551 and 1073 follow these steps.
551)1071(1
551
----------------
522)551(1
522
------------
29)522(18
29
---------
232
232
------------
XXX
So,HCF of 551 and 1073 is 29.
To find HCF of 551 and 1073 follow these steps.
551)1071(1
551
----------------
522)551(1
522
------------
29)522(18
29
---------
232
232
------------
XXX
So,HCF of 551 and 1073 is 29.
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