Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
76 comments Page 6 of 8.
Sushma said:
1 decade ago
Its simple let a * b = 4107 now 37 is common in both a and b so 37*some number(x)=4107 so solve this 37*x=4107 so 4107/37 =111.
Roy said:
1 decade ago
What is co-prime nos?
Bipin said:
1 decade ago
Simply as we know:
LCM x HCF = product of co-prime or a x b.
Given that,
Product of two nos = 4107
HCF = 37
LCM = ?
Finally we can put the value on above formula,
LCM*HCF = product.
LCM = 4107/37.
LCM = 111 Answer.
LCM x HCF = product of co-prime or a x b.
Given that,
Product of two nos = 4107
HCF = 37
LCM = ?
Finally we can put the value on above formula,
LCM*HCF = product.
LCM = 4107/37.
LCM = 111 Answer.
MAHESH said:
1 decade ago
X*Y = 4107.
X*37 = 4107.
X = 4107/37.
X = 111.
X*37 = 4107.
X = 4107/37.
X = 111.
Vijesh said:
1 decade ago
SIMPLE METHOD:
PRODUCT OF THE TWO NUMBERS = LCM*HCF.
4107 = 37*LCM.
LCM = 111.
PRODUCT OF THE TWO NUMBERS = LCM*HCF.
4107 = 37*LCM.
LCM = 111.
Aman Kaushik said:
1 decade ago
Just a very simple method.
Product of the two number/ HCF.
4107/37 = 111.
Product of the two number/ HCF.
4107/37 = 111.
Mukesh said:
1 decade ago
HCF means greater number divisible. 37 is dividable by 1 and 37. Apart from this 37 is highest. So divide 4107/39=111.
Rups said:
1 decade ago
H.C.F*L.C.M = a*b.
37*L.C.M = 4107.
L.C.M = 4107/37.
L.C.M = 111.
37*L.C.M = 4107.
L.C.M = 4107/37.
L.C.M = 111.
Prasann said:
1 decade ago
Direct formula we had please check.
Product of two numbers (a x b) = L.C.M x H.C.F.
Given H.C.F = 37 and product = 4107.
Therefore, L.C.M = Product/H.C.F = 4107/37 = 111.
Product of two numbers (a x b) = L.C.M x H.C.F.
Given H.C.F = 37 and product = 4107.
Therefore, L.C.M = Product/H.C.F = 4107/37 = 111.
Ramkumar LS said:
1 decade ago
Simplest method in few secs.
Formula:
Product of two numbers = HCF X LCM.
Given:
Product of two numbers = 4107, HCF = 37 and LCM = unknown.
Now, simply substitute the given values.
4107 = (37 X unknown).
Lets keep unknown on one side and bring 37 below.
Unknown = 4107/37.
Therefore, Unknown= 111 //simply divide 4107 by 37.
Note: When you do this on paper this will only take 2 secs to find.
Formula:
Product of two numbers = HCF X LCM.
Given:
Product of two numbers = 4107, HCF = 37 and LCM = unknown.
Now, simply substitute the given values.
4107 = (37 X unknown).
Lets keep unknown on one side and bring 37 below.
Unknown = 4107/37.
Therefore, Unknown= 111 //simply divide 4107 by 37.
Note: When you do this on paper this will only take 2 secs to find.
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