Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
76 comments Page 5 of 8.
Sachin said:
1 decade ago
Best method is to use the co primes as it in the given explanation.
4107/37=111, which is not the correct solution.
4107/37=111, which is not the correct solution.
Priya said:
1 decade ago
This will work on co-primes. If two numbers are not coprimes then how should we find out ?
Rahul said:
1 decade ago
Thanks Pannu.
Anand said:
1 decade ago
Simply multiply the value 37*111=4107
Jyoti said:
1 decade ago
Simply divide the product with H.C.F
i.e 4107/37=111
i.e 4107/37=111
Mehar said:
1 decade ago
Easy way to get ans:divide the product with H.C.F
-->4107/37=111;
-->4107/37=111;
PVNARASIMHARAO said:
1 decade ago
L.C.M * H.C.F=FIRSTNUMEBR * SECONDNUMBER
IF THEY ARE COPRIMES
IF THEY ARE COPRIMES
DHEERAJ SINGH said:
1 decade ago
HCF = 37.
Product of two numbers are = 4107.
HCFxLCM = Product of two nos.
37xLCM = 4107.
LCM = 111.
Since LCM is the least no which will be divided by the number.
So the number will be a multiple of 111, so from above options 111 is the only multiple of 111. So answer is 111.
Product of two numbers are = 4107.
HCFxLCM = Product of two nos.
37xLCM = 4107.
LCM = 111.
Since LCM is the least no which will be divided by the number.
So the number will be a multiple of 111, so from above options 111 is the only multiple of 111. So answer is 111.
Vinay said:
1 decade ago
It is not essential that LCM will always be greater number
@ ravi
your explanation are good
@ ravi
your explanation are good
Sugandh said:
1 decade ago
Let we have two numbers 2 and 6...
now product of these two numbers=12
hcf(2 and 6)=2
lcm=6
now we hav 2 find d greater numbr that is 6..how it comes..it is simply d lcm...
it means we hav to find out the lcm....so somply divide the product f two numbers by their hcf to get the lcm;,,,,
12/2=6 =greatest number
now product of these two numbers=12
hcf(2 and 6)=2
lcm=6
now we hav 2 find d greater numbr that is 6..how it comes..it is simply d lcm...
it means we hav to find out the lcm....so somply divide the product f two numbers by their hcf to get the lcm;,,,,
12/2=6 =greatest number
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