Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
101
107
111
185
Answer: Option
Explanation:

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

Greater number = 111.

Discussion:
77 comments Page 5 of 8.

Thulsi said:   1 decade ago
Best method by verification.

Divide 4107 by 37 we get 111.

Sachin said:   1 decade ago
Best method is to use the co primes as it in the given explanation.

4107/37=111, which is not the correct solution.

Priya said:   1 decade ago
This will work on co-primes. If two numbers are not coprimes then how should we find out ?

Rahul said:   1 decade ago
Thanks Pannu.

Anand said:   2 decades ago
Simply multiply the value 37*111=4107

Jyoti said:   2 decades ago
Simply divide the product with H.C.F
i.e 4107/37=111

Mehar said:   2 decades ago
Easy way to get ans:divide the product with H.C.F

-->4107/37=111;

PVNARASIMHARAO said:   2 decades ago
L.C.M * H.C.F=FIRSTNUMEBR * SECONDNUMBER
IF THEY ARE COPRIMES

Ramesh said:   1 decade ago
Given HCF = 37.

Product of two numbers is = 4107.

As HCF is greatest divisor so the number will be 4107/37 = 111.

The greatest number is 111.

Sugandh said:   1 decade ago
Let we have two numbers 2 and 6...
now product of these two numbers=12
hcf(2 and 6)=2
lcm=6
now we hav 2 find d greater numbr that is 6..how it comes..it is simply d lcm...
it means we hav to find out the lcm....so somply divide the product f two numbers by their hcf to get the lcm;,,,,

12/2=6 =greatest number


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