Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
79 comments Page 5 of 8.
Thulsi said:
1 decade ago
Best method by verification.
Divide 4107 by 37 we get 111.
Divide 4107 by 37 we get 111.
Sachin said:
2 decades ago
Best method is to use the co primes as it in the given explanation.
4107/37=111, which is not the correct solution.
4107/37=111, which is not the correct solution.
Priya said:
2 decades ago
This will work on co-primes. If two numbers are not coprimes then how should we find out ?
Rahul said:
2 decades ago
Thanks Pannu.
Anand said:
2 decades ago
Simply multiply the value 37*111=4107
Jyoti said:
2 decades ago
Simply divide the product with H.C.F
i.e 4107/37=111
i.e 4107/37=111
Mehar said:
2 decades ago
Easy way to get ans:divide the product with H.C.F
-->4107/37=111;
-->4107/37=111;
PVNARASIMHARAO said:
2 decades ago
L.C.M * H.C.F=FIRSTNUMEBR * SECONDNUMBER
IF THEY ARE COPRIMES
IF THEY ARE COPRIMES
ABHAY KUMAR said:
3 months ago
Very helpful. Thanks for explaining it.
Sandip said:
1 decade ago
We know that HCF*LCM = Product of two number.
So the other no is = 4107/37 = 111.
So the other no is = 4107/37 = 111.
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