Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
79 comments Page 4 of 8.
Manikanta said:
8 years ago
For a*b =3. So.
1*3 =3.
And.
3*1 = 3.
(May be a=1 then b=2).
(May be b=1 then a=2).
Then how you are deviating to 1, 2 and 2, 1? Please tell me.
1*3 =3.
And.
3*1 = 3.
(May be a=1 then b=2).
(May be b=1 then a=2).
Then how you are deviating to 1, 2 and 2, 1? Please tell me.
Abitha said:
8 years ago
Here for ab=3, its possibilities are (1, 2) & (2, 1) Only right?
Please, anyone, help me.
Please, anyone, help me.
Ravi said:
1 decade ago
@ vani
Its false statement that LCM is the the greater no.
We know as a*b = lcm*hcf
Here 4107 = lcm*37
lcm = 111 or (3*37)
so a*b = 37*3*37
or a*b = (37*3)*37
or a*b = 37*(3*37)
So greater no. is 3*37=111
Its false statement that LCM is the the greater no.
We know as a*b = lcm*hcf
Here 4107 = lcm*37
lcm = 111 or (3*37)
so a*b = 37*3*37
or a*b = (37*3)*37
or a*b = 37*(3*37)
So greater no. is 3*37=111
Aparna said:
9 years ago
No need of these complications.
As per formula PRODUCT OF TWO NOS. = LCM * HCF.
hence, substitute from the question wherein,
4107=lcm * 37.
4107/37 = 111 =lcm.
As per formula PRODUCT OF TWO NOS. = LCM * HCF.
hence, substitute from the question wherein,
4107=lcm * 37.
4107/37 = 111 =lcm.
Arun said:
9 years ago
Thank you all.
Priya.E said:
9 years ago
Thnks @Pannu.
Sharad said:
6 years ago
When we find the LCM as 111, why does it mean that one of the number is 111 and the other is 37. They are just factors and multiples. Please anyone explain.
Vani said:
1 decade ago
Can LCM always be the greatest no.?
Muthusamy said:
1 decade ago
Thanks raju and thulasi.
111 said:
1 decade ago
Thanks anand
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