Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
78 comments Page 4 of 8.
Vani said:
1 decade ago
Can LCM always be the greatest no.?
Muthusamy said:
1 decade ago
Thanks raju and thulasi.
Arun said:
9 years ago
Thank you all.
ZUBAYRUL HASAN said:
9 years ago
As 37 is the HCF of these numbers. So, we can take the smaller number is 37 and greater is 37x.
A.C, 37*37x=4107,
or, x= 4107÷(37*37),
or, x =3,
Now, the greatest number is 37*3=111 (Ans).
A.C, 37*37x=4107,
or, x= 4107÷(37*37),
or, x =3,
Now, the greatest number is 37*3=111 (Ans).
Priya.E said:
9 years ago
Thnks @Pannu.
Marisankar said:
6 years ago
What is co-prime?
Sharad said:
6 years ago
When we find the LCM as 111, why does it mean that one of the number is 111 and the other is 37. They are just factors and multiples. Please anyone explain.
Asif said:
9 years ago
How we come to know that in this question we have to find LCM, in the question we have to find the greater number? please.
111 said:
1 decade ago
Thanks anand
Thulsi said:
1 decade ago
Best method by verification.
Divide 4107 by 37 we get 111.
Divide 4107 by 37 we get 111.
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