Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
77 comments Page 3 of 8.
Raj said:
2 decades ago
Simple method:
LCM=product of co primes/HCF
=>4107/37=111
LCM=product of co primes/HCF
=>4107/37=111
(1)
Harika said:
2 weeks ago
4107 product of 37.
This is divisible by 111.
So, the answer is 111.
This is divisible by 111.
So, the answer is 111.
Surya said:
10 years ago
Properties of LCM & HCF.
We know, product of 2 numbers = (LCM of 2 numbers) * (HCF of 2 numbers).
So, 4107 = LCm of 2 numbers * 37,
Then, We get 111.
We know, product of 2 numbers = (LCM of 2 numbers) * (HCF of 2 numbers).
So, 4107 = LCm of 2 numbers * 37,
Then, We get 111.
Ramesh M said:
9 years ago
Same doubt for me @Sangeetha.
Please can anyone help us.
Please can anyone help us.
Anirudh said:
9 years ago
1250 is the product of x and y. What is the HCF of x and y?
Solve and explain the solution.
Solve and explain the solution.
OM SHANKAR PRASAD said:
9 years ago
@Anirudh.
Because we can make pair of (10*125) , (50*25), (250*5), (2*625), (1*1250), so HCF is varying, so I think more data need.
Because we can make pair of (10*125) , (50*25), (250*5), (2*625), (1*1250), so HCF is varying, so I think more data need.
Asif said:
9 years ago
How we come to know that in this question we have to find LCM, in the question we have to find the greater number? please.
Priya.E said:
9 years ago
Thnks @Pannu.
Raushan said:
10 years ago
In the any condition you can take, it is not only for co-prime. It will work for all.
And two numbers are said to be co-prime if the HCF is 1.
And two numbers are said to be co-prime if the HCF is 1.
ZUBAYRUL HASAN said:
9 years ago
As 37 is the HCF of these numbers. So, we can take the smaller number is 37 and greater is 37x.
A.C, 37*37x=4107,
or, x= 4107÷(37*37),
or, x =3,
Now, the greatest number is 37*3=111 (Ans).
A.C, 37*37x=4107,
or, x= 4107÷(37*37),
or, x =3,
Now, the greatest number is 37*3=111 (Ans).
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