Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
76 comments Page 3 of 8.
Sanjivani said:
1 decade ago
Co prime means not get co-prime (1, 3).
(1)
Harwani Payal said:
6 years ago
Assume Two numbers p and q.
Multiply them with 37.
37p*37p.
Now, 37p*37p = 4107.
1369pq = 4107.
pq = 4107/1369.
pq = 3.
Multiply them with 37.
37p*37p.
Now, 37p*37p = 4107.
1369pq = 4107.
pq = 4107/1369.
pq = 3.
OM SHANKAR PRASAD said:
9 years ago
@Anirudh.
Because we can make pair of (10*125) , (50*25), (250*5), (2*625), (1*1250), so HCF is varying, so I think more data need.
Because we can make pair of (10*125) , (50*25), (250*5), (2*625), (1*1250), so HCF is varying, so I think more data need.
Nidhu said:
6 years ago
We know that;
H.C.F * L.C.M = product of two numbers.
37* x = 4107,
x=4107/37,
x = 111.
H.C.F * L.C.M = product of two numbers.
37* x = 4107,
x=4107/37,
x = 111.
Manikanta said:
7 years ago
For a*b =3. So.
1*3 =3.
And.
3*1 = 3.
(May be a=1 then b=2).
(May be b=1 then a=2).
Then how you are deviating to 1, 2 and 2, 1? Please tell me.
1*3 =3.
And.
3*1 = 3.
(May be a=1 then b=2).
(May be b=1 then a=2).
Then how you are deviating to 1, 2 and 2, 1? Please tell me.
Manikanta said:
7 years ago
For a*b =3. So.
1*3 =3.
And.
3*1 = 3.
(May be a=1 then b=2).
(May be b=1 then a=2).
Then how you are deviating to 1, 2 and 2, 1? Please tell me.
1*3 =3.
And.
3*1 = 3.
(May be a=1 then b=2).
(May be b=1 then a=2).
Then how you are deviating to 1, 2 and 2, 1? Please tell me.
Abitha said:
7 years ago
Here for ab=3, its possibilities are (1, 2) & (2, 1) Only right?
Please, anyone, help me.
Please, anyone, help me.
Muthusamy said:
1 decade ago
Thanks raju and thulasi.
Aparna said:
8 years ago
No need of these complications.
As per formula PRODUCT OF TWO NOS. = LCM * HCF.
hence, substitute from the question wherein,
4107=lcm * 37.
4107/37 = 111 =lcm.
As per formula PRODUCT OF TWO NOS. = LCM * HCF.
hence, substitute from the question wherein,
4107=lcm * 37.
4107/37 = 111 =lcm.
Arun said:
8 years ago
Thank you all.
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