Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
77 comments Page 7 of 8.
Kajal said:
1 decade ago
How we come to know that in this question we have to find LCM, in the question we have to find the greater number, reply as soon as possible?
MJani said:
1 decade ago
Explain any short method to solve this problem? Its too long of 4107/1369.
Nikita said:
1 decade ago
Please explain the given evaluation properly. By co-prime method only.
Arif said:
1 decade ago
But in case of smaller number?
Prakruthi said:
1 decade ago
a*b = HCF*LCM;
4107 = 37*LCM;
LCM = 4107/37;
LCM = 111;
4107 = 37*LCM;
LCM = 4107/37;
LCM = 111;
Sandip said:
1 decade ago
We know that HCF*LCM = Product of two number.
So the other no is = 4107/37 = 111.
So the other no is = 4107/37 = 111.
Ramesh said:
1 decade ago
Given HCF = 37.
Product of two numbers is = 4107.
As HCF is greatest divisor so the number will be 4107/37 = 111.
The greatest number is 111.
Product of two numbers is = 4107.
As HCF is greatest divisor so the number will be 4107/37 = 111.
The greatest number is 111.
DHEERAJ SINGH said:
1 decade ago
HCF = 37.
Product of two numbers are = 4107.
HCFxLCM = Product of two nos.
37xLCM = 4107.
LCM = 111.
Since LCM is the least no which will be divided by the number.
So the number will be a multiple of 111, so from above options 111 is the only multiple of 111. So answer is 111.
Product of two numbers are = 4107.
HCFxLCM = Product of two nos.
37xLCM = 4107.
LCM = 111.
Since LCM is the least no which will be divided by the number.
So the number will be a multiple of 111, so from above options 111 is the only multiple of 111. So answer is 111.
David said:
10 years ago
H.C.F * L.C.M.
Product of that two numbers is this equality only in case of co-prime numbers or all other numbers also.
Can anyone please confirm me.
Product of that two numbers is this equality only in case of co-prime numbers or all other numbers also.
Can anyone please confirm me.
Prasad said:
1 decade ago
Generally ((hcf*lcm)/(n1*n2)) = 1.
So here the hcf is=37;
Let lcm is =x;
The product of two numbers = 4107.
So,
Now ((hcf*lcm)/(n1*n2)) = 1.
(37*x)/(4107) = 1.
By solving above expression we get x value as 111.
So here the hcf is=37;
Let lcm is =x;
The product of two numbers = 4107.
So,
Now ((hcf*lcm)/(n1*n2)) = 1.
(37*x)/(4107) = 1.
By solving above expression we get x value as 111.
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