Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 13)
13.
Reduce | 128352 | to its lowest terms. |
238368 |
Answer: Option
Explanation:
128352) 238368 ( 1 128352 --------------- 110016 ) 128352 ( 1 110016 ------------------ 18336 ) 110016 ( 6 110016 ------- x ------- So, H.C.F. of 128352 and 238368 = 18336. 128352 128352 ÷ 18336 7 Therefore, ------ = -------------- = -- 238368 238368 ÷ 18336 13
Discussion:
59 comments Page 2 of 6.
Rashmitha said:
2 years ago
In the options, mostly the denominator is 13.
If we divide 238368 by 13, we can get the exact number which divides both 128352 and 238368.
238368/13=18336 whose last digit is 6.
In 128352 the last digit is 2.
If multiply 6 by 7, then we can get the last digit as 2.
So, the answer is 7/13.
If we divide 238368 by 13, we can get the exact number which divides both 128352 and 238368.
238368/13=18336 whose last digit is 6.
In 128352 the last digit is 2.
If multiply 6 by 7, then we can get the last digit as 2.
So, the answer is 7/13.
(12)
Sachin said:
2 years ago
(2*2*2*2*2*3*7*191)/(2*2*2*2*2*3*2483)
Gives;
(7*191)/(2483) = 7/13.
Gives;
(7*191)/(2483) = 7/13.
(7)
Known said:
1 year ago
Anyone, please explain me in detail to understand the answer.
(6)
Punni said:
5 years ago
@All.
According to me, the solution is;
1. We simply take out the factors by just orally dividing...which i hope we can all do it at this level.
2. So 128352 = 2 x 64176.
= 2 x 2 x 32088,
= 4 x 4 x 8022,
= 16 x 2 x 4011,
= 32 x 3 x 1337,
= 32 x 3 x 7 x 191.
3. Similarly, 238368 = 4 x 59592.
= 4 x 4 x 14898,
= 16 x 2 x 7449,
= 32 x 3 x 1337,
= 32 x 3 x 13 x 191.
4. Now when we put this in form, 32 x 3 x 7 x 191/ 32 x 3 x 13 x 191 = 7/13.
Hope, this helps you all to understand.
According to me, the solution is;
1. We simply take out the factors by just orally dividing...which i hope we can all do it at this level.
2. So 128352 = 2 x 64176.
= 2 x 2 x 32088,
= 4 x 4 x 8022,
= 16 x 2 x 4011,
= 32 x 3 x 1337,
= 32 x 3 x 7 x 191.
3. Similarly, 238368 = 4 x 59592.
= 4 x 4 x 14898,
= 16 x 2 x 7449,
= 32 x 3 x 1337,
= 32 x 3 x 13 x 191.
4. Now when we put this in form, 32 x 3 x 7 x 191/ 32 x 3 x 13 x 191 = 7/13.
Hope, this helps you all to understand.
(6)
Barath s said:
4 years ago
Reduce the no to 12/23.
it is approx 1/2.
So, find an option that is close to 1/2(i.e) 7/13.
it is approx 1/2.
So, find an option that is close to 1/2(i.e) 7/13.
(3)
Mel said:
2 years ago
@All.
We can Find the unit place by cross-multiplying.
We can Find the unit place by cross-multiplying.
(3)
Kavita said:
4 years ago
@Punni.
How can we take out factors of such a big number? Explain, please.
How can we take out factors of such a big number? Explain, please.
(1)
HEMA said:
6 years ago
For suppose let us assume their hcf be X.
Then ( X*u)/(X*v)= 128352/238368.
Where u,v are the co primes
Eg: here in case of option A : u =3 and v= 4 similarly for remaining options also..!!
Here the question gets easily solved if we verify the options as follows........
--Firstly if u observe both the options i.e A and C are satisfying the numerator and denominator.
i.e 128352 is divisible by both 3 and 7
238368 is divisible by both 4 and 13
Since both the options are satisfying we need to go for another option elimination process which will be b/w option A and C
---here if u observe clearly for option A the last digit of X in case of X*u is not satisfied by the last digit of X in case of X*...but it is not the case with option C as the last digits of both X's in case X*u and X*v are same .......
Which implies option C is the correct answer.
Note:-
**The above process won't even take more than 5min and this process reduces the complexity of solving as it won't involve finding the exact HCF value**
Then ( X*u)/(X*v)= 128352/238368.
Where u,v are the co primes
Eg: here in case of option A : u =3 and v= 4 similarly for remaining options also..!!
Here the question gets easily solved if we verify the options as follows........
--Firstly if u observe both the options i.e A and C are satisfying the numerator and denominator.
i.e 128352 is divisible by both 3 and 7
238368 is divisible by both 4 and 13
Since both the options are satisfying we need to go for another option elimination process which will be b/w option A and C
---here if u observe clearly for option A the last digit of X in case of X*u is not satisfied by the last digit of X in case of X*...but it is not the case with option C as the last digits of both X's in case X*u and X*v are same .......
Which implies option C is the correct answer.
Note:-
**The above process won't even take more than 5min and this process reduces the complexity of solving as it won't involve finding the exact HCF value**
(1)
Poovarasan said:
9 years ago
The formula is;
Product of LCM & HCF = product of two numbers.
Product of LCM & HCF = product of two numbers.
(1)
Vaishak said:
9 years ago
Guys, I have an idea over here for quick solution of this problem at first, 128352/238368 = 0.53 find this fraction value by dividing the stuff given in the question and then from all the options of answer divide each of them and find the fraction like 3/4 = 0.75 and so on for other four and finally when the decimal value matches with the above found value it is the answer i.e is 7/13 = 0.53, that's it.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers