Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 13)
13.
Reduce 128352 to its lowest terms.
238368
3
4
5
13
7
13
9
13
Answer: Option
Explanation:
 128352) 238368 ( 1
         128352
         ---------------
         110016 ) 128352 ( 1
                  110016
                 ------------------  
                   18336 ) 110016 ( 6       
                           110016
                           -------
                                x
                           -------
 So, H.C.F. of 128352 and 238368 = 18336.
 
             128352     128352 ÷ 18336    7
 Therefore,  ------  =  -------------- =  --
             238368     238368 ÷ 18336    13                    
Discussion:
59 comments Page 2 of 6.

Rashmitha said:   2 years ago
In the options, mostly the denominator is 13.

If we divide 238368 by 13, we can get the exact number which divides both 128352 and 238368.
238368/13=18336 whose last digit is 6.
In 128352 the last digit is 2.
If multiply 6 by 7, then we can get the last digit as 2.
So, the answer is 7/13.
(12)

Sachin said:   2 years ago
(2*2*2*2*2*3*7*191)/(2*2*2*2*2*3*2483)
Gives;
(7*191)/(2483) = 7/13.
(7)

Known said:   1 year ago
Anyone, please explain me in detail to understand the answer.
(6)

Punni said:   5 years ago
@All.

According to me, the solution is;

1. We simply take out the factors by just orally dividing...which i hope we can all do it at this level.

2. So 128352 = 2 x 64176.
= 2 x 2 x 32088,
= 4 x 4 x 8022,
= 16 x 2 x 4011,
= 32 x 3 x 1337,
= 32 x 3 x 7 x 191.

3. Similarly, 238368 = 4 x 59592.
= 4 x 4 x 14898,
= 16 x 2 x 7449,
= 32 x 3 x 1337,
= 32 x 3 x 13 x 191.

4. Now when we put this in form, 32 x 3 x 7 x 191/ 32 x 3 x 13 x 191 = 7/13.

Hope, this helps you all to understand.
(6)

Barath s said:   4 years ago
Reduce the no to 12/23.
it is approx 1/2.

So, find an option that is close to 1/2(i.e) 7/13.
(3)

Mel said:   2 years ago
@All.

We can Find the unit place by cross-multiplying.
(3)

Kavita said:   4 years ago
@Punni.

How can we take out factors of such a big number? Explain, please.
(1)

HEMA said:   6 years ago
For suppose let us assume their hcf be X.
Then ( X*u)/(X*v)= 128352/238368.

Where u,v are the co primes

Eg: here in case of option A : u =3 and v= 4 similarly for remaining options also..!!
Here the question gets easily solved if we verify the options as follows........

--Firstly if u observe both the options i.e A and C are satisfying the numerator and denominator.

i.e 128352 is divisible by both 3 and 7
238368 is divisible by both 4 and 13

Since both the options are satisfying we need to go for another option elimination process which will be b/w option A and C

---here if u observe clearly for option A the last digit of X in case of X*u is not satisfied by the last digit of X in case of X*...but it is not the case with option C as the last digits of both X's in case X*u and X*v are same .......

Which implies option C is the correct answer.

Note:-

**The above process won't even take more than 5min and this process reduces the complexity of solving as it won't involve finding the exact HCF value**
(1)

Poovarasan said:   9 years ago
The formula is;

Product of LCM & HCF = product of two numbers.
(1)

Vaishak said:   9 years ago
Guys, I have an idea over here for quick solution of this problem at first, 128352/238368 = 0.53 find this fraction value by dividing the stuff given in the question and then from all the options of answer divide each of them and find the fraction like 3/4 = 0.75 and so on for other four and finally when the decimal value matches with the above found value it is the answer i.e is 7/13 = 0.53, that's it.
(1)


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